Append list as not one.

[Anonymous]

Hello

I get still terrible in my works.

Anyway, all I want to need helping is that if I have some list variable, I want to append list variable individually.

If i use append function such as (setq A(append '( 1 2) ' ( 4 5))), then i will get A that is '(1 2 4 5). However, this is not I want.

I want to get A that is ('(1 2) '(4 5)).

Thanks.

[john.uhden]

(append A (list B))

[ВeekeeCZ]

(append '((1 2)) '((4 5)))

[dbroad]

I think you're using the wrong function. Try cons

(setq a (cons '(4 5) nil))
(setq a (cons '(1 2) a))

The results are:

((4 5))

and

((1 2) (4 5))

Results should never include the quote function IMO.

[john.uhden]

Okay then...
(append B (list A)) 😉

You know that I agree with consing over appending. Just having fun.

[phanaem]

(list '(1 2) '(3 4)) = ((1 2) (3 4))