Eurocode 7 - Partial Factors

Eurocode 7 - Partial Factors

Anonymous
Not applicable
1,081 Views
4 Replies
Message 1 of 5

Eurocode 7 - Partial Factors

Anonymous
Not applicable

Hi,

 

I'm trying to design a pad footing( 6.0x6.0x2.0m) according to EC7 - DA2.

The imposed loads are

 

DEAD LOADS:

600ΚΝ vertical load plus self weight of foundation automatically calculated by Robot(6.00x6.00x2.00x24.53=1766.16KN)

 

LIVE LOADS:

300KN horizontal load

3000kNm moment at the the top of footing.

 

The design combination for soil capacity is 1.00DL+1.50LL

 

In the calculation note it seems that the total vertical dead load is calculated with a partial factor 1.00 for the imposed dead load and with 1.35 for the self weight: Ν=1.35x1766.16+1.00x600=2984.32KN.

 

Is this calculation correct?

 

Also I would like to ask if it's possible to design according to DA2* (maybe by editting some. rgl file?)

 

Thank you.

0 Likes
Accepted solutions (1)
1,082 Views
4 Replies
Replies (4)
Message 2 of 5

Artur.Kosakowski
Autodesk Support
Autodesk Support

I think it is correct. As both combinations are used for verification. The live load "generates" eccentricity and large eccentricity is unfavourable. The 1.35 factor actually stabilizes the situation despite generation larger stress in soil.

 

foundation1.png

 

For DA2 - is this what you need?

 

DA2.png

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.

 

 

 



Artur Kosakowski
0 Likes
Message 3 of 5

Anonymous
Not applicable

Hi Artur,

 

thanks for the reply.

 

What I don't understand is why in ULS3 and ULS4 the selfweight of the foundation has a partial factor 1.35 and the dead load has one of 1.00.

SELF WEIGHT: 6.00x6.00x2.00x24.53=1766.16KN

N=600.00KN

Ntot=1.35x1766.16+1.00x600.00=2984.32KN

 

I believe the correct load should have been (for a favourable action of the dead loads)

Ntot=1.00x1766.16+1.00x600.00=2366.16KN

 

I mean DA2* (with an asterisk) where partial factors are applied all together  γΕ( Ε)<1 /γR(R).

 

 

 

0 Likes
Message 4 of 5

Artur.Kosakowski
Autodesk Support
Autodesk Support
Accepted solution

It is assumed that for the certain load types depending on the verification type only maximal or minimal load factor is used. Please check:

http://help.autodesk.com/cloudhelp/2016/ENU/RSAPRO-UsersGuide/files/GUID-69B741C7-D958-4C83-B4C6-E98...

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
0 Likes
Message 5 of 5

Anonymous
Not applicable

Thank you.

0 Likes