Automatic calculation Lay and Laz

Automatic calculation Lay and Laz

Anonymous
Not applicable
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Message 1 of 5

Automatic calculation Lay and Laz

Anonymous
Not applicable

Good Morning,

 

I installed Robot 2017 and the calculation of Lay and Laz is not right.

 

It takes into account the smallest length and verification results are different from those of Robot 2016.

 

https://www.dropbox.com/s/6k03m5xm4lfn2yg/problemaKauto.rtd?dl=0

 

problemaKauto.PNG

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Message 2 of 5

Artur.Kosakowski
Autodesk Support
Autodesk Support

I can't see any difference betwen RSA 2016 and RSA 2017

 

 

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
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Message 3 of 5

Artur.Kosakowski
Autodesk Support
Autodesk Support

I just wanted to check if the movie I posted helped. 



Artur Kosakowski
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Message 4 of 5

Anonymous
Not applicable

Good Morning,

 

Something happened that made me believe that the problem was only Robot 2017.

 

I think it's great that the problem arises 2016 Robot and Robot 2017.

 

Why is he using that KL / r crazy?

 

Thank you.

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Message 5 of 5

Artur.Kosakowski
Autodesk Support
Autodesk Support

As (I hope) you (already) know the results are displayed in location where there is maximal ratio. In case there are number of points with the same ratio the first found is displayed.

 

Let's look at bar 220. If you divide the value of axial force by the resistance the ratio with the precision to two digits after dot will be the same in several locations along the bar so the one from x= 0L is displayed. As you defined restrains in any node along the bar the distance from its origin to the first one is very short and this is he reason for lay and laz being very small. 

 

Personally I'd create model and assigned bar types in in a different way (so that chord bar doesn't end in between the diagonals) so i made a quick test (see the results for bar 4) which confirm what I explained above (the ration for axial force to resistance for two digits precision is still 0.05 despite unrestrained buckling length being longer.

 

So far I can't see any issue with lay and laz.

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
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