Set Normal to create rebar

[Anonymous]

Hi! I'm using the function Rebar, but I have problems when my lines aren't liying in the normal 1,0,0 : 0,1,0 and 0,0,1

How to get the normal from this set of coordinates:

23.73542   0.65550   2.67900   
23.73542   0.65550   2.15279
23.65644   1.55819   1.55100    ---PA
23.25398   6.15835   1.55100    ---PB
23.17501   7.06104   2.15279
23.17501   7.06104   2.67900

I guess that I must be use PA - PB for it but it doesn't work..

Any idea about it?

Thanks in advance.

Luis.

[jeremytammik]

Dear Louis,

I suggest that you search the Revit SDK samples globally for the NewRebar function calls and see how they handle it there.

Have you done that yet?

Cheers,

Jeremy

[Anonymous]

Hi Jeremy! ... I'm followong that and my problem is to get the vector (normal).... 

 rebar = Rebar.CreateFromCurves(doc, RebarStyle.Standard, RT, null, null, el, setHook.SetNormal, GetCurves(item), RebarHookOrientation.Right, RebarHookOrientation.Right, true, true);

and It's working when the coordinates set to the plane: 

BasisX

BasisY

BasisZ

but when it'not doesn't work!

Thanks to answer!

Luis.

[Mustafa.Salaheldin]

What is "setHook.SetNormal"? and What are you exactly want to do?

[Anonymous]

Hi!

setHook.SetNormal is a class that I've créate to evaluate the normal from a set of coordinates..... and another functions.

my function evaluate y the coordinates have a common axis, and return a xyz normal.... I've already created rebars when all coordinates were liying on an axis for example:

set of coordinates 1: the normal is new XYZ(0, 1, 0);

3.92706 1.92077 -0.76725
3.92706 1.92077 -0.04750
0.24606 1.92077 -0.04750
0.24606 1.92077 -0.76725 

set of coordinates 2: the normal is new XYZ(1, 0, 0);

3.74456 0.01327 -0.76930
3.74456 0.01327 -0.07000
3.74456 7.70327 -0.07000
3.74456 7.70327 -0.76930

set of coordinates 3: the normal is new XYZ(0, 0, 1);

3.56151 -0.00073 -0.20350
3.94556 -0.00073 -0.20350
3.94556 7.71727 -0.20350
3.56151 7.71727 -0.20350

and so far so good.... I was creating rebars without problema in the element in Revit

here is the hardest part

-16.28757 7.02486 1.89219
-16.29806 7.08438 1.93684
-16.29806 7.08438 3.31943
-16.27909 6.97681 3.42700
-16.26392 6.89074 3.42700

How to get the normal?

and about your question! a rebar

Thanks!

Luis!

[Mustafa.Salaheldin]

Do you calculate the Normal vector from a Surface, Line or manually? Please provide your code and Revit sample project so I may can help.

[Anonymous]

Hi,

About Normal, i set for all case as:

normal = new XYZ(1, (-(x2 - x1) / (y2 - y1)), 0);

[FAIR59]

You need 3 points to define a plane (and a normal)

Given 3 distinct points a,b, and c, you can find the normal as the crossproduct between b-a and c-a.

XYZ normal = b.Subtract(a).CrossProduct(c.Subtract(a));

[Anonymous]

My Plane set by cordinate

Examble for rebar Beam

P1: the first Beam (x1,y1,z1)

P2: the end beam (x2,y2,z2)

I set P3 in plane Oxy => P3 (x1,y1,0) or (x2,y2,0)

=> my plane (P1,P2,P3)

=> Normar as above for all case

=> Similar column