Firstly, you did not answer the OP's question. He want to load only one form
into Acad no matter how many times his command is executed.
Secondly, your advice is against Autodesk's recommendation. In the document,
it is clearly stated that a form/dialogbox should be shown by using
Application.ShowModalDialog()
Application.ShowModelessDialog()
Showing a form/dialog with .NET Form.Show()/ShowDialog() could lead to
unexpectced result, accroding to the doucment.
To the OP:
You can declare the Form as static member of the class, and only create the
form instance if it has not been created.
class Test
{
static MyForm frm=null;
[CommandMethod("TestCmd")]
public static void TestCommand()
{
//You only instantiate MyForm object when it hasn't been created
if (frm==null)
{
frm=new MyForm()
}
//Then show it here. You could set its Visible to True, or call
Application.ShowModal(Modeless)Dialog()...
}
}
"afghari" wrote in message news:
[email protected]...
use .net methods for show your form . you don`t need
Application.ShowModalDialog for showing the forms that created by .net .
in C# I follow this way for showing the form as dialog :
Form frm=new DrawClothoid();
frm.Showdialog();
or this for simple showing :
Form frm=new DrawClothoid();
frm.Show();
and consider that change to false the ShowInTaskbar peropertie of form.
Message was edited by: afghari
