RelationConstraint + integer

[ztravnicky]

Hi everyone,

if I create integerBox in Relation Constraint, how do I set some value into input 'a' ?

lAbsDampFacBox = lConstraintRelation.CreateFunctionBox( 'Number', 'Integer' )

lConstraintRelation.SetBoxPosition( lAbsDampFacBox, -250, -50 )

I was trying ...

lAbsDampFacBoxIn = FindAnimationNode( lAbsDampFacBox.AnimationNodeInGet(), 'a' )

lAbsDampFacBoxIn.Add = int(80)

and many others approaches, but no success. 😞

Zbynek

[ztravnicky]

this "trick" doesnt work anymore ... 

http://forums.autodesk.com/t5/Python/Set-Value-in-Relation-Constraint/m-p/3969777/highlight/true#M20...

[stevkalinowski · Accepted solution]

[code]
def FindAnimationNode(pAnimNode, pPlugName):
   for a in pAnimNode.Nodes:
      if a.Name == pPlugName:
         return a

   return None

lConstraintRelation = FBConstraintRelation('StaticDataRelation')
lAbsDampFacBox = lConstraintRelation.CreateFunctionBox( 'Number', 'Integer' )
lConstraintRelation.SetBoxPosition( lAbsDampFacBox, -250, -50 )

lAbsDampFacBoxIn = FindAnimationNode( lAbsDampFacBox.AnimationNodeInGet(), 'a' )
lAbsDampFacBoxIn.WriteData( [80] )

[/code]

When calling the "WriteData" method, you have to put the arg in a list.  I'm not certain why.