Is there a need for optimization in the algorithm used by Inventor for Sheet Metal Flat Pattern views?
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Hello everyone,
I'm facing an issue with the Flat Pattern Length and Width Dimensions obtained from the Flat Pattern view in Autodesk Inventor. When I create a Flat Pattern view, I understand that Inventor rotates the part to align the largest edge with the X-axis. The dimensions I get from this view differ significantly from the dimensions I obtain when manually rotating the flat pattern view.
In Picture - 1, the Flat Pattern view created by Inventor shows dimensions of 1207.3 mm and 2936.92 mm. In Picture - 2, I manually adjusted the flat pattern view (rotated the part), resulting in dimensions of 1217.63 mm and 2813.95 mm.
Upon calculating the area using these dimensions, Picture - 2 has a smaller area than Picture - 1. I believe that Picture - 2 is more desirable, as it facilitates better nesting and reduces material consumption.
Consider another sheet metal part that is longer than the one attached. If I follow the approach in Picture - 1 and obtain dimensions exceeding 3048 mm, which is the length of a 10-ft sheet, I would need to purchase a 12-ft sheet. However, if I rotate the part and the dimensions come in just under 3048 mm, I can efficiently utilize a 10-ft sheet without the need to buy a larger 12-ft sheet.
My question is why doesn't Inventor take into account the combination of area and the rotation of the longest edge to provide users with the best output, ultimately minimizing material consumption? I've attached the Sheet Metal Part file for reference.
Let me know if I am missing anything @johnsonshiue @Curtis_Waguespack @Gabriel_Watson
Thank you
Picture - 1
Picture - 2