How to get remainder of a division.

[sbadavath]

Hi all,

I am new to iLogic & don't know much about coding, need help with this.

Say I have A=Some_number (10 for explanation's sake) & B=Another_number (3 for this example).
X=Remainder of (A/B) which is 1 here.

X=1.

How do write this in iLogic.

Thanks in advance.

[WCrihfield]

Get 'absolute' value of A/B, then subtract the Integral part of that value, to get the remainder, which in this case is .333___.  Then multiply that remainder by B, to get the remaining portion of 3 that remains.

A = 10
B = 3
X = Abs((A / B) -Truncate(A / B))
MsgBox("X = " & X, , "")
MsgBox("X*B = " & X * B, , "")

[Curtis_Waguespack]

Hi @sbadavath 

Welcome to the forum.

In addition to WCrihfield's method you can use the Mod operator to find the remainder also:

x = 10 Mod 3

MsgBox(x)

I hope this helps.
Best of luck to you in all of your Inventor pursuits,
Curtis
http://inventortrenches.blogspot.com

[WCrihfield · Accepted solution]

Hi @sbadavath.  There is actually a much simpler way to do this...I don't know why I didn't think of this before.  You can use the 'Mod' operator.  This is precisely what it was made for.  Here is a link to its official description.

A = 10
B = 3
Y = A Mod B
MsgBox("Y = " & Y, , "")