USING PARAMETERS FOR A ROCKER BOGIE HELP

USING PARAMETERS FOR A ROCKER BOGIE HELP

Anonymous
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Message 1 of 9

USING PARAMETERS FOR A ROCKER BOGIE HELP

Anonymous
Not applicable

So I m trying to optimize a rocker bogie suspension system but I am running into a few problems using the parameters. I am having problems with my parameter "L4" it should be a Patagonian equation for a triangle length: (S1^2+(2R))^(-1) but when I try it on my calculator I get different values then the nominal. I also get the text in red. I hope this is the cause for it not being able to finish the constraints since i am fairly certain my parameters I derived are correct. I attached images of what I am trying to do and what the inventor software is showing

 

thanks, Sage Edwards

 

 

CORRECTION: found that I can define L4 as L4=H1

also the angle between the bogie arms is constrained to 90deg

 

Update: I am thinking i need to revisit my equations but if i can get an explanation for the red text that would be great

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1,049 Views
8 Replies
Replies (8)
Message 2 of 9

JDMather
Consultant
Consultant

It doesn't look to me like you have accounted for your units.

 

I recommend that you right out the equation on paper with the units included.


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Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


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Message 3 of 9

Anonymous
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my equations are not dependent on units they are just basic trig and geometry equations. I am checking my equations on paper now but that doesn't explain the red error text. Did I type it in wrong? 

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Message 4 of 9

Anonymous
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Additional question: I would like to make R (radius of wheel) to be a variable) Is this something I can do? 

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Message 5 of 9

JDMather
Consultant
Consultant

@Anonymous wrote:

my equations are not dependent on units .... 


R is in mm
S1 is in mm

L4 is mm

 

Inventor doesn't forget the units.

 

I am doing some experimenting, I suspect that you cannot use implied negative ^-1ul


-----------------------------------------------------------------------------------------
Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


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Message 6 of 9

JDMather
Consultant
Consultant

@Anonymous wrote:

my equations are not dependent on units .... 


R is in mm  You have R=100mm which you are then squaring
S1 is in mm You have S1=286.706mm which you are then squaring

L4 is mm

 

Inventor doesn't forget the units.

 

I am doing some experimenting, I suspect that you cannot use implied negative ^-1ul


-----------------------------------------------------------------------------------------
Autodesk Inventor 2019 Certified Professional
Autodesk AutoCAD 2013 Certified Professional
Certified SolidWorks Professional


Message 7 of 9

Anonymous
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ok thankyou i didnt see anything for squarroots so i just did that
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Message 8 of 9

Anonymous
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Accepted solution

Dear sedwar22,

 

Putting a quantity to the negative first power divides one by the quantity.  x^-1 = 1/x

 

What you would want to do to take the square root in the parameters is use the sqrt() function.

 

You might also want to re-enter your argument and put parenthesis around the powers. sqrt((S1^2ul)-((2 ul*R)^2))

 

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Message 9 of 9

Anonymous
Not applicable

whoops i meant to have it to the power of 1/2 lol but yes i have tried putting the powers in () but thanks for the sqrt function i didnt know it was used here since i didn't see it on the list of commands i could use. but thanks i will give it a go

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