"IF" Statement in "Equation" Cells in Parameter Dialogue

[BeKirra]

Is it possible to insert "IF" statement in the equation cell (see below - it can be an IPT/IAM file)?

Here is an example.

If "d0" > 20, then "d1" = 10, otherwise "d1" = 5

I've tried but no success.

(BTW I am not trying to create an ipart.)

Thanks In advance.

[kacper.suchomski]

Hi

You can do this via iLogic.

[BeKirra]

So "IF" statement won't work in equation cell?

For a simple task I don't prefer using iLogic.

[pcrawley]

No, there is no "If" in the parameters dialogue box.  I understand not wanting to use iLogic for "a simple task", but sometimes, it really is the "simplest" solution:

If d0 > 20 Then
	d1 = 10
	Else
	d1 = 5	
End If

Because the iLogic is code operates on parameters, you don't need any special triggers - it just works.

[johnsonshiue]

Hi! This is a very interesting request. Certainly, a simple iLogic rule as Peter mentioned above will work. There are other ways to solve it. Here is a solution by using parametric functions, which will lead to the logical result. Please note that when d0 = 20.00001mm, the result will be zero, which wrong. But I don't believe anybody would add have such dimension.

sign(( d0 - 20.00001 mm ) / 1 mm) * 10 mm + sign(( 20.00001 mm - d0 ) / 1 mm) * 5 mm

Many thanks!

[pcrawley]

Genius (as usual) @johnsonshiue !

[NachoShaw]

I'm going to chime in here, hi Johnson 🙂

IF in equations makes sense, I common topic among users. Why is iLogic not the preferred choice? While iLogic is ok, there are some company policies the do not permit code,especially when iLogic remains unprotected. ILogic makes it hard to share files with a function dependency so code share persists.

All that's needed if the inclusion of 'IF'

[BeKirra]

Thanks to @pcrawley and @johnsonshiue 

Both your codes work.

But it is not what I am after.

Edit: @johnsonshiue 

Sorry, I mentioned your method is not what I am after because your equation is a bit of complicate.

@NachoShaw Thanks for your input.

I agree with your comment.

👍

[johnsonshiue]

Hi Folks,

Certainly, having the ability to set logical statement in a parametric expression makes perfect sense. But it always comes down to the cost and the priority. Nothing is free. Please feel free to submit it to Inventor Ideas forum (https://forums.autodesk.com/t5/inventor-ideas/idb-p/v1232) so that the users can vote for it. The project teams will review and prioritize it accordingly.

Many thanks!

[NachoShaw]

We don't expect it to be free which is why we all pay a subscription 😎

It already exists in the ideas station

[johnsonshiue]

Hi Nacho,

The "free" I am talking about is the cost to implementing such workflow. Though it might seem "easy" to implement, it can lead to costly technical implications.

Many thanks!

[BeKirra]

---

@johnsonshiue wrote:

Hi Folks,

Certainly, having the ability to set logical statement in a parametric expression makes perfect sense. But it always comes down to the cost and the priority. Nothing is free.

...

---

Understand and agree.

When Inventor updates or new release come out for install, it obviously costed to Autodesk's implement.

But updating and upgrading Inventor is how Autodesk is to keep it's users.

As a user, I personally expect to get samll functions like this one added in or improved before next release.

[johnsonshiue]

Hi! Submitting these ideas to Inventor Ideas forum or participating in the Inventor Feedback Community is the best way to escalate the need.

Many thanks!

[J-Camper]

This is a bit more simplified version of @johnsonshiue , equation:

5 mm + 5 mm * sign(floor(d0 / 20 mm))

Or this if your step size will always be 5mm:

5 mm * ( 1 ul + sign(floor(d0 / 20 mm)) )

Then you can create sudo Else If statements like this:

5 mm * ( 1 ul + sign(floor(d0 / 20 mm)) + sign(floor(d0 / 40 mm)) + sign(floor(d0 / 60 mm)) )

The sign operator feels very much like an If operator in this case.


Edit:
I just realized you were asking for greater than 20 mm not greater than or equal to 20mm.  The floored division above will do greater than or equal to.  A simple subtraction will do greater than:

5 mm * ( 1 ul + sign(d0 - 20 mm) )

[NachoShaw]

Be sure to use ABS(Sign) as I've had negative value instances using Sign in the past

[J-Camper]

Interesting.  The documentation for Sign that I have read seems like it should be a purely binary output [Functions, prefixes, and algebraic operators].  Do you have an example of any outcome that is not a 1 or 0?