If the door is in static equilibrium, the sum the moments of the known and unknown forces about the lower hinge will be zero. Solve that equation for the unknown force. If you know the door's CG, you can add in the moment load due to its weight too.
Here is an interesting guide to statics 101: http://www.fao.org/docrep/015/i2433e/i2433e03.pdf Look at example 6.3.
More Examples: http://www.ce.jhu.edu/lori/statics/hw02.pdf
Something like 0=1500mm*F-600mm*100kg. (can you spot my error?) You should convert the kg (mass) into Newtons (force).
When you do these calculations, make sure you use the perpendicular distance between the pivot point and the line-of-action of each force. If not, you will need to resolve the forces and distances into x,y,z coordinates and then write and solve an equation for each direction.
Steve Walton
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