Cycle def 7.0 and cycle def 19.0

[fusion3608MQJC]

I would like to get output from a too orientation point on Heidenhain.

When we program I manual we use cycle 7 before we rotate with cycle 19.

Output like this makes it easier to compare 2D drawing measurement with NC code.

; ROTATE TO PLANE START

CYCL DEF 7.0 DATUM SHIFT

CYCL DEF 7.1 X157.154

CYCL DEF 7.2 Y-60.000

CYCL DEF 7.3 Z-50.000

CYCL DEF 19.0 BEARBEITUNGSEBENE

CYCL DEF 19.1 A90.000 B0.000 C105.000

L B+Q120 C+Q122 R0 FMAX

L X+20.000 Y+12.500 FMAX

L Z+25.000 R0 FMAX M3 M

L Z+0.000 R0 F2500 M3 M

L X+111.000 Y+12.500 F1500

L Z+25.000 R0 FMAX M3 M

CYCL DEF 7.0 DATUM SHIFT

CYCL DEF 7.1 X0

CYCL DEF 7.2 Y0

CYCL DEF 7.3 Z0

CYCL DEF 19.0 BEARBEITUNGSEBENE

CYCL DEF 19.1 A0.000 B0.000 C0.000

L B+Q120 C+Q122 R0 FMAX

Is it possible to get output like this in fusion 360?

[boopathi.sivakumar]

Hi @fusion3608MQJC 

While post processing in the NC programs dialog you can set the tilted workplane method as shown below

[bodk]

Hi,

I need to offset the output to work from selected shift point.

To do this I need to:

CYCL DEF 7.0 DATUM SHIFT

CYCL DEF 7.1 X157.154

CYCL DEF 19.0 BEARBEITUNGSEBENE

CYCL DEF 19.1 A90.000 B0.000 C105.000

Then XYZ must come shiftet point.

what do I need to do in postprocessor?

Bo

[AdamKunzo]

Hello @bodk @fusion3608MQJC 

If you need help with the post processor, you can send me a message. I offer post processor modifications as a service and I'll be happy to assist you with your request. 

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