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Creating a relation between 2 junctions based on a math function

8 REPLIES 8
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Message 1 of 9
miguelon1602
271 Views, 8 Replies

Creating a relation between 2 junctions based on a math function

Hi everyone. I'm developing a scissor mechanism (see image), and I want to start with the junctions' movement relations to get it to work. However, I haven't found any way to create a junction that's based on a math function. I have the function on paper, but I don't know how to apply it. it would be between the rotation and prismatic junction that are on the same point. How can I do this?

 

TIA

 

miguelon1602_0-1690572988210.png

 

8 REPLIES 8
Message 2 of 9

@miguelon1602 

Can you File>Export your *.f3d file to your local drive and then Attach it here to a Reply?

Also indicate your desired Equation.

Message 3 of 9
jeff_strater
in reply to: miguelon1602

you can use an expression in a Motion Link between two joints.  I assume here that you want to relate the two Revolute joints in the image with a Motion Link?

 


Jeff Strater
Engineering Director
Message 4 of 9

file attached. the formula I want to apply is d=-50*cos(theta), being d the movement of the lineal joint (negative to go closer to 0), and theta the angle on the rev joint that's on the same point

Message 5 of 9
miguelon1602
in reply to: jeff_strater

that's not what I'm asking about. I want to create a motion link between the lineal and the revolute joint that are on the same point, but with a non-linear relation (I want the distance travelled by the lineal joint to rely on the cosine of the angle of the revolution joint that's on the same point)

Message 6 of 9
jeff_strater
in reply to: miguelon1602

OK, well, that was just a guess.  No, I don't think that you can create that kind of a relationship in a Motion Link.  Someone smarter may find a way, but I don't know of one.  You can simulate it with Motion Study.


Jeff Strater
Engineering Director
Message 7 of 9
miguelon1602
in reply to: miguelon1602

UPDATE: In the end, I applied a revolution joint with a 2:1 ratio link to another one of the existent revolution joints, and now the mechanism behaves as it should

Message 8 of 9
jhackney1972
in reply to: miguelon1602

That sure is a far cry from the formula of motion you posted in message #5!


"If you find my answer solved your question, please select the Accept Solution icon"

John Hackney
Retired

Beyond the Drafting Board


Message 9 of 9
miguelon1602
in reply to: jhackney1972

The formula was to get the middle holes to move fully vertical, just so the mechanism behaved as expected (a scissor lifting mechanism). I ended up trying another route to see if I could get it to work, and I ended up getting the result with a different way of applying joints

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