Help with editing a post in VS code

[JeffreyTKomorowski]

Hey everyone, I am currently working off my dads plasma cutter / water jet machine and Im trying to match his codes to my post. 

One of the issues I am having is that I tried to download Autodesk Fusion 360 Post Processor Utility and on mac I can't seem to get it to work but finding a line in. my Gcode where I need to edit the post. That is 1 problem I am having but very minor I would say. Im not sure if it matters but I am on a mac. I can't seem to find help really on youtube videos for mac setup for this. 

The big issue I am having is that I am trying to add in the line that is a subprogram for the feed rates on his controller / machine. 

P0119 L1

I want the machine to run M98 and when it does run that I want it to add "P0119 L1" with it. 

I was able to go into the code and see where it calls either M98 or M9. I tired to add a string to the ternary operator as shown in the picture but when I run the post it all comes back as an error. I'm not super good with JS but I know a little and my guess is that it's because it's returning M format

(block of code where it determines M98 or M9)

(an edit by adding a string at the end of the ternary hoping it would work but it just caused an error every time I tried to set up the post processor and generate g code) 

(an image of the code that is being generated from fusion)

\

(what I want to achieve in the M98 line)

[Sq_14]

try this ...

writeBlock(mFormat.format(power ? 98 : 9)) + writeBlock("P0119 L1");

or, depending on the output line 

writeBlock(mFormat.format(power ? 98 : 9)) + writeBlock(" P0119 L1");

[JeffreyTKomorowski]

this works partially, it's generating a new block of code regardless of the ternary outcome. What I am looking for is if its M98, I want the code to follow to be P0119 L1 (in the same line I believe?? if not I can maybe make it work on separate lines 

[carl.j.barker · Accepted solution]

Using a + after a numerical literal will be trying to do a mathematic addition rather then a concatenation.

try 

writeBlock(mFormat.format(power ? 98 : 9) , power ?  "P0119 L1" : "");

or

writeBlock(mFormat.format(power ? 98 : 9) + conditional(power == true, " P0119 L1"));

If you need the option to separate blocks with a space then -

writeBlock(mFormat.format(power ? 98 : 9) , power ?  "P0119" : "" , power ?  "L1" : "");   may be better

[Sq_14]

thank you for posting this, the power of conditional and it's syntax helps a lot ..

In regards to my '+' error .... i guess i shouldn't post at 4,30 am right before having the coffee  

[JeffreyTKomorowski]

I used this as the correct solution. I was able to achieve my goal by creating a new function that runs within the original function to add it. However, after trying your last block of code it works better by keeping it all on the same line.