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Hello,
Can I start off by saying, I think I fully understand the following(INSUNITS):
But where does -DWGUNITS fit in?
I understand that DWGUNITS sets the units that are being used in the current drawing, but when you change the DWGUNITS it gives you an option to match the INSUNITS to the DWGUNITS and whether or not you want to scale upon insertion.
So does this then mean if you choose "yes" for these two options that this overrides whatever INSUNITS, INSUNITSDEFSOURCE and INSUNITSDEFTARGET are set to? If these commands are all set to unitless, that should mean objects are not scaled when inserting, but when setting the DWGUNITS, there is no unitless option and so therefore if you press "yes", does it override what INSUNITS, INSUNITSDEFSOURCE and INSUNITSDEFTARGET are set to.
Below I've shown a table giving the results I obtained when trying to find an answer to this question and why doesn't setting "Scale other objects from other drawings upon insert: Y/N" to No have any effect. I've also attached the 2 drawings I've used, no.1 is the source drawing for the block and no.2 is the drawing I tried inserting it into.
Any help greatfully received.
Thanks in advance.
IUB = INSUNITS of Block
IUS = INSUNITSDEFSOURCE
IUT = INSUNITSDEFTARGET
IUD = INSUNITS of Drawing
DU = DRAWING UNITS
SOI = Scale other objects from other drawings upon insert: Y/N
MCI = Mettre en corresponsdance Insunits et les uités de dessin: Y/N
SEI = Scale existing objects in current drawing: Y/N
Block is non annotive & is a circle radius 20 units, its source drawing has drg units set to mm (via -dwgunits).
1 = “, 4 = mm; 6 = m,
IUB– | IUS– | IUT– | IUD– | DU | SOI | MCI | SEI | Result |
4 | 0 | 0 | 6 | 3, mm | Y | N | Y | r = 0,02mm |
4 | 0 | 0 | 6 | 3, mm | N | N | Y | r = 0,02mm |
4 | 0 | 0 | 6 | 3, mm | Y | N | N | r = 0,02mm |
4 | 0 | 0 | 6 | 3, mm | N | N | N | r = 0,02mm |
0 | 0 | 0 | 0 | 6, m | N | N | N | r = 20m |
0 | 0 | 0 | 0 | 6, m | Y | N | N | r = 20m |
0 | 0 | 0 | 6 | 6, m | Y | N | N | r = 20m |
0 | 0 | 0 | 6 | 6, m | Y | Y | N | r = 20m |
0 | 0 | 0 | 6 | 6, m | Y | Y | Y | r = 20m |
0 | 0 | 0 | 6 | 6, m | N | Y | Y | r = 20m |
¡Resuelto! Ir a solución.