operator carries a single box during the entire process

[esteban_b2]

[ FlexSim 20.1.3 ]

Hi!

In my model, I want that the operator that takes the box from the classification, goes to the sensor and the same operator with the same box he took to the sensor, goes to the corresponding queue.

I mean I want that the operator handles the same box during the process.

OPERATOR classification.fsm

[Jeanette_Fullmer · Accepted solution]

Hello @Esteban B2,

To have the same operator who brings the box to the processor be the one to take it to queue you will need to use a process flow with your model. I used this post as a reference. It might be helpful for you to review it as well.

My model removes several connections in the model and removes the dispatcher. The Process Flow with be able to provide the logic for everything removed from the model. Try recreating my process flow in your model so you learn how process flow can work within your model.

An important thing to notice about my process flow is that there is a create TS activity and finish TS activity. These activities allow for all the task between them too be grouped into one task, so that when other task request come in for the operator those requests do not interrupt the sequence of tasks given in the process flow. If the Create TS was not there you could possibly see an operator go off and do another task and then come back to the box even though you want the operator to stay with the box.

Here is my attached model for your reference. Please let me know if you would like any part of it explained.

Process-With-Same-Operator-Process-Flow.fsm

[jeff_nordgren]

@Esteban B2,

Attached is your model with the changes that I've made to it. This is how I would go about doing what you are describing.

Just added a model update (JN2). This is probably the one that works best.

Take a look at the model and see if a solution like this would work for you.

Thanks.

operator-classification-JN1.fsm

operator-classification-JN2.fsm

[Ben_WilsonADSK]

Hi @Esteban B2, was Jeanette F's or Jeff Nordgren's answer helpful? If so, please click the red "Accept" button on one of their answers. Or if you still have questions, add a comment and we'll continue the conversation.

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