I want an operator to move 3 three boxes to one conveyor, then another conveyor.

I want an operator to move 3 three boxes to one conveyor, then another conveyor.

reece_h
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Message 1 of 5

I want an operator to move 3 three boxes to one conveyor, then another conveyor.

reece_h
Not applicable

[ FlexSim 18.2.2 ]

I have made a simple 3D model including (source, operator, two conveyors and a sink). I want the operator to move 3 boxes to the first conveyor, then three boxes to the next, then to repeat the process. Basically alternating three to each conveyor. How can this be done?

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Message 2 of 5

joerg_vogel_HsH
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@Reece H, please attach your model.

You can build a ProcessFlow logic counting the exit of the source and moving the items to the conveyors.

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Message 3 of 5

joerg_vogel_HsH
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Simply but not looking nice is a hard coded approach. You connect each conveyor as often as the conveyor receive an item with the source by an object connection (A-type). Then you choose in the source the Send To Port function picklist option Round Robin. The items are leaving the source in the order the source is connected to the conveyors. First output connection receives the first item, second connected output connection the second item, .. , n-th item is sent to the n-th output connection, (n-th + 1) item is sent to the first output connection again, (n-th + 2) item to the second output connection and so on.

A operator is only supporting this logic by transporting the items. He decides nothing else then to execute the transport task sequences in the order he has received the sequences.

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Message 4 of 5

reece_h
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trial-mixing-table.fsm

Hi @Jörg Vogel, please see above. I want to elaborate. I need operator2 to collect 3 boxes from Queue1 consecutively and deposit them in the connected conveyor before moving to the next task. This rule should apply to all other tasks of moving items associated with Operator 2 (between the three queues and three conveyors in the model)

Can you advise?

Reece

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Message 5 of 5

joerg_vogel_HsH
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@Reece H, please ask your request as a new question, thanks.

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