Calculating work done to a fluid by a rotor and stator in a sealed unit
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Hi,
I am looking to calculate the work done to a fluid that is sealed inside a unit between a rotor and a stator type design (no inward or outward flow). Essentially the rotor is rotated by an external motor to a specific RPM to agitate the fluid between the two solid bodies, there is space for the fluid to move between the solids.
I want to be able to change fluid parameters and cavity shape (fluid contained between the Rotor and Stator design) by changing the Rotor and Stator design and compare the results.
(Ultimately I would also like to calculate the heat transfer from the internal fluid through to an external body but i realise this is another question in itself.)
I am very new to CFD and have worked through a few of the tutorials and read a couple of threads on here but nothing specifically like this.
I have been advised to use boundary conditions on rotational speed, fluid, temperature (assumed), kinematic viscosity and density with a turbulence model of k-w SST. The solution scheme for pressure-velocity coupling is the SIMPLE scheme. The simulations of the rotor/casing covered are single phase, steady state, isothermal in a moving reference frame.
What i have done so far is:
- modelled the fluid cavity as a solid in Inventor then pulled it by itself into CFD 2019. I've read that cutting this into a section would give faster results. So I cut it to a 90° section of the cavity.
- change the material to a fluid (I'm starting with water to get it to work but I have specific heat transfer fluid I would like to model that I have created in 'My Materials')
- added the boundary conditions but I am unsure as to where these go in regards to the many faces i could select since we don't have an inlet or outlet
- Autosize the mesh. I've also read that a really fine mesh is needed for this sort of simulation.
- hope for the best 🙂
Any help with how and where to enter these boundary conditions would be very much appreciated. Thank you for reading if you have made it this far.
Thanks
Ray