Diesel Expressions for file path

[ben.williamsMPBQ3]

Hi all!, 

I would like to be able to access file names that are at the end of a file path, however one file name in the middle of the path changes in length. e.g.

2019/ 123456 'Name length changes'/Drawings/Mechanical/Preliminary

I can get Diesel to get '2019' and '123456' with no problem as the character lengths never change. Is there a way Diesel can count backwards? As the folder names 'Mechanical' & 'Preliminary' don't change in character length.

So if there was a way for Diesel to just grab the last two folders, count the folder string characters backwards there would be no change in character length.

Any help would be greatly appreciated.

[ВeekeeCZ]

DIESEL has very limited functionality. Look HERE at the list of all functions available.

Unless you're on LT rather move to LISP.

[ben.williamsMPBQ3]

Unfortunately I don't quite understand the code, I have been able to manipulate the numbers of characters on

existing codes to get the desired folder name from a path.

One code I was using was able to delete the last character of a string, which has made me think can a code count the characters in a file path backwards. If it can, I can get the file names of the last two folders and the fact that a previous folder name changes in length would not affect the last two folder names.

Am I making any sense? :s