I am designing a part that has the shape of a catenary. In order to make it right the first time, I want to shape the catenary af the exact equation and not by making a spline between points.
I am not a math genius nor an Inventor genius, so I someone could tell me the input (see attachment) I would be pleased!
The equation I need to draw (metric) is this: f(x) = -(2.0272/2)*(e^(x/2.0272)+e^(-x/2.0272))
The part is 3800mm wide and 2200mm high (see attachment 2)
I am looking forward to your suggestions!
Solved! Go to Solution.
I could not get this to look exactly like your picture. I think my equation is correct. Here is what I used for the equations. Set your units to Meters.
x(t) = t
yt) = -1.0136 ul * ( pow(2.71828 ul;( t / 2.0272 ul )) + pow(2.71828 ul;( -t / 2.0272 ul )))
tmin = -1.9 tMax = 1.9
Here is what this looks like. Maybe you can tweak it and get it to work. If I get some more time, I will also look at this again.
Thank you very much for your reply. I worked out perfect. I am sorry, however, to tell you that I provided you the wrong equation - no wonder that you had trouble getting it right. The correct equation is f(x)= -(1063.35/2)*(e^(x/1063.35)+e^(-x/1063.35))
Sorry for that. However, I simply change the 2.0272 with 1063.35 and there it was!
You saved my day!
Log into access your profile, ask and answer questions, share ideas and more. Haven't signed up yet? Register