topic Re: how to eq a shape to an adaptive point in Revit Architecture Forum

how to eq a shape to an adaptive point

Anonymous — Thu, 25 Jun 2020 09:40:32 GMT

i'm trying to make a "tree" that has adaptive points. the basic shape of the tree is a rectangle and i want each rectangle's center to be the point.

when i make an instance parameter and change the number to bigger or smaller, it doesn't originate from the middle point that i need- that is the reference point.

attaching pics- can see that the first width is 30, then when i try to change it to 60, it expands not from the middle.

important to say is that i don't have the eq sign when drawing the rectangle.

when i draw the rectangle,i start from the middle point and go up(half the length i need) and than right(half width that i need) and than continue with the regular lengths so the rectangle will be the right size from beginning and will be centered.

Re: how to eq a shape to an adaptive point

martijn_pater — Thu, 25 Jun 2020 14:33:17 GMT

I'm not entirely sure what you're trying to do, but I think the answer is nesting of another adaptive family...

Re: how to eq a shape to an adaptive point

ToanDN — Thu, 25 Jun 2020 16:15:04 GMT

What prevents you from placing eq eq dim to the point.

Re: how to eq a shape to an adaptive point

barthbradley — Thu, 25 Jun 2020 18:50:17 GMT

What about hosting Reference Points to Work Planes of other Reference Points and driving their Offsets through Parameters?

Check out Message #4 and its attachments:

https://forums.autodesk.com/t5/revit-architecture-forum/generic-model-attic-steel-sheets-full-parametrical/td-p/9596475

Re: how to eq a shape to an adaptive point

Anonymous — Thu, 25 Jun 2020 19:01:06 GMT

eq sign doesn't appear.

i could do 2 dims and then i'd have the eq option.

thing is if i do 2 dims, that means it'll be 2 different instance type parameters, i think.

i just gave up on the perfectionism in this case and did the points as revit wants it, from an edge and expands towards the right/ left and not from center wise.

Re: how to eq a shape to an adaptive point

ToanDN — Thu, 25 Jun 2020 22:04:03 GMT

May I ask why you think building a tree as a generic adaptive family is a good idea?

Re: how to eq a shape to an adaptive point

Anonymous — Fri, 26 Jun 2020 05:19:23 GMT

i have beams that are under a floor(hidden in pic) and from their edges i need something i can control- the branches attach to the beam(to the sphere at the edge of the beam) and then the other edge of that branch i can move around and place them on intersections of the mass. each branch is a different length too, a bit longer/ shorter.

look at the picture below, hope that explains it.

if you have any other ideas, i'll gladly read them! i've been only learning from these posts.

Re: how to eq a shape to an adaptive point

martijn_pater — Fri, 26 Jun 2020 06:42:44 GMT

😅I have no idea what you're trying to make... maybe post some more plans/sections/3d etc, elaborate some more...

Re: how to eq a shape to an adaptive point

Anonymous — Fri, 26 Jun 2020 15:40:06 GMT

@martijn_pater

this is a studio project i'm doing in uni.

a is a beam holding a floor. b is a sphere that's attached to the beam from both edges. c are "legs/ branches" that are attached to d- intersection of pattern based family.

beam and sphere (a+b) are built in one family.

c is an adaptive family so i could move the edges around when i see where the intersection (d) is and place it there.

any ideas that are smarter than mine?

Re: how to eq a shape to an adaptive point

Anonymous — Mon, 29 Jun 2020 15:07:38 GMT

solution received from the link below:

https://www.youtube.com/watch?v=YOxNKu76rx8&t=2s

Re: how to eq a shape to an adaptive point

martijn_pater — Tue, 30 Jun 2020 07:08:06 GMT

@AnonymousWell I don't know the ins and outs ofcourse, but I think I would look at keeping these two constructions seperate with a ring / triangular truss maybe in its design. Just a thought though, probably you have a project supervisor to help you along... Regarding the adaptive family question, it seems you've found the answer.