topic Re: Divide a segment equally with a range in visual basic in Inventor Programming Forum

Divide a segment equally with a range in visual basic

Anonymous — Wed, 16 Jan 2013 01:44:27 GMT

How do you divide a segment equally with a range in visual basic?

example-

length is 144 in

range- 7.5 - 9in

answer- (18) at (range 8 in)

like to know how to do this in Visual Basic so I can create some rules and forms in iLogic

thx

Re: Divide a segment equally with a range in visual basic

Anonymous — Wed, 16 Jan 2013 07:48:22 GMT

Hi there,

There are loads of ways to do this. Here is one:

Sub Demo()
Dim Length As Double
Dim Range As Double

    Length = 144
    Range = 8

    MsgBox (Answer(Length, Range))
End Sub

Function Answer(L As Double, R As Double)
    Answer = L / R
End Function

This should be a start for you

Cheers

Jon.

Re: Divide a segment equally with a range in visual basic

Anonymous — Wed, 16 Jan 2013 12:34:33 GMT

Thanks Jon

- can this be done within the parameters instead of iLogic?

Re: Divide a segment equally with a range in visual basic

Anonymous — Wed, 16 Jan 2013 14:55:16 GMT

Yes, it's not difficult, but can be tricky and frustrating! Parameters can be pretty fickle when it comes to units.

If you have:

d0 = Length (in)

d1 = Range (in)

d2 = Answer/Segments (ul)

Note that the inch units cancel each other to give a unitless value (in/in = ul).

Cheers

Jon.