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    <title>topic Re: VBA and Inventor in Inventor Programming Forum</title>
    <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899323#M131131</link>
    <description>&lt;P&gt;i speak Russian,&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;is the contour, the creation of 5 sketch lines (Figure), which creates a cutout, you need to programmatically determine which forms the face of one line sketch. (the whole model is created programmatically)&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;есть контур, созданый из 5 эскизных линий (рисунок), который создает вырез, нужно программно определить грань которую образует 1 линия эскиза. (вся модель создаеться программно)&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;IMG alt="Снимок.PNG" src="https://forums.autodesk.com/t5/image/serverpage/image-id/51659i8DF506B08A0665E9/image-size/original?v=mpbl-1&amp;amp;px=-1" align="center" border="0" title="Снимок.PNG" /&gt;&lt;/P&gt;</description>
    <pubDate>Tue, 30 Apr 2013 13:09:24 GMT</pubDate>
    <dc:creator>Anonymous</dc:creator>
    <dc:date>2013-04-30T13:09:24Z</dc:date>
    <item>
      <title>VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3896068#M131128</link>
      <description>&lt;P&gt;Hi all,&amp;nbsp;&lt;/P&gt;&lt;P&gt;On a forum I didn't look for as I know badly language.&lt;BR /&gt;Problem essence: there is a detail and in it cut (rectangular) how to define a side in cut if the line the parent (the outline line) this side is known.&lt;BR /&gt;I am sorry for my bad English.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Visual Express Studio 2010 (basic)&lt;/P&gt;&lt;P&gt;Inventor 2013&lt;/P&gt;</description>
      <pubDate>Sun, 28 Apr 2013 12:07:26 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3896068#M131128</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-04-28T12:07:26Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3897576#M131129</link>
      <description>&lt;P&gt;Are you asking how to perform a dynamic cut feature with an established sketch?&lt;/P&gt;</description>
      <pubDate>Mon, 29 Apr 2013 19:07:25 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3897576#M131129</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-04-29T19:07:25Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3897700#M131130</link>
      <description>&lt;P&gt;&lt;SPAN&gt;Chris, that's what I got as well - hard to tell.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;Seferot, what languages do you speak?&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;</description>
      <pubDate>Mon, 29 Apr 2013 20:26:55 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3897700#M131130</guid>
      <dc:creator>jdkriek</dc:creator>
      <dc:date>2013-04-29T20:26:55Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899323#M131131</link>
      <description>&lt;P&gt;i speak Russian,&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;is the contour, the creation of 5 sketch lines (Figure), which creates a cutout, you need to programmatically determine which forms the face of one line sketch. (the whole model is created programmatically)&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;есть контур, созданый из 5 эскизных линий (рисунок), который создает вырез, нужно программно определить грань которую образует 1 линия эскиза. (вся модель создаеться программно)&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;IMG alt="Снимок.PNG" src="https://forums.autodesk.com/t5/image/serverpage/image-id/51659i8DF506B08A0665E9/image-size/original?v=mpbl-1&amp;amp;px=-1" align="center" border="0" title="Снимок.PNG" /&gt;&lt;/P&gt;</description>
      <pubDate>Tue, 30 Apr 2013 13:09:24 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899323#M131131</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-04-30T13:09:24Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899506#M131132</link>
      <description>&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;Я надеюсь,&lt;/SPAN&gt; &lt;SPAN&gt;я понимаю вашу&lt;/SPAN&gt; &lt;SPAN&gt;проблему правильно&lt;/SPAN&gt;&lt;SPAN&gt;.&lt;/SPAN&gt; &lt;SPAN&gt;Вы&lt;/SPAN&gt; &lt;SPAN&gt;хотите использовать&lt;/SPAN&gt; &lt;SPAN&gt;экструзионную&lt;/SPAN&gt; &lt;SPAN&gt;эскиз&lt;/SPAN&gt;&lt;SPAN&gt;, чтобы сократить&lt;/SPAN&gt; &lt;SPAN&gt;часть?&lt;/SPAN&gt; &lt;SPAN&gt;Вы сказали, что&lt;/SPAN&gt; &lt;SPAN&gt;вся&lt;/SPAN&gt; &lt;SPAN&gt;часть создана с помощью&lt;/SPAN&gt; &lt;SPAN&gt;кода&lt;/SPAN&gt;&lt;SPAN&gt;, правильно?&lt;/SPAN&gt; &lt;SPAN&gt;Означает ли это,&lt;/SPAN&gt; &lt;SPAN&gt;у вас есть свободный&lt;/SPAN&gt; &lt;SPAN&gt;доступ к&lt;/SPAN&gt; &lt;SPAN&gt;эскизу&lt;/SPAN&gt;&lt;SPAN&gt;, который нужно вырезать&lt;/SPAN&gt; &lt;SPAN&gt;с&lt;/SPAN&gt;&lt;SPAN&gt;?&lt;/SPAN&gt; &lt;SPAN&gt;Вы должны&lt;/SPAN&gt; &lt;SPAN&gt;быть в состоянии найти&lt;/SPAN&gt;&lt;SPAN&gt;, например, в&lt;/SPAN&gt; &lt;SPAN&gt;файле помощи&lt;/SPAN&gt; &lt;SPAN&gt;API&lt;/SPAN&gt; &lt;SPAN&gt;о том, как&lt;/SPAN&gt; &lt;SPAN&gt;экструзия&lt;/SPAN&gt; &lt;SPAN&gt;эскиз.&lt;/SPAN&gt; &lt;SPAN&gt;В основном один раз&lt;/SPAN&gt; &lt;SPAN&gt;у вас есть&lt;/SPAN&gt; &lt;SPAN&gt;эскиз&lt;/SPAN&gt;&lt;SPAN&gt;, необходимо создать&lt;/SPAN&gt; &lt;SPAN&gt;профиль, вы&lt;/SPAN&gt; &lt;SPAN&gt;затем создать&lt;/SPAN&gt; &lt;SPAN&gt;определение&lt;/SPAN&gt; &lt;SPAN&gt;выдавливания&lt;/SPAN&gt;&lt;SPAN&gt;,&lt;/SPAN&gt; &lt;SPAN&gt;и, наконец,&lt;/SPAN&gt; &lt;SPAN&gt;экструзии&lt;/SPAN&gt; &lt;SPAN&gt;с использованием определения&lt;/SPAN&gt;&lt;SPAN&gt;.&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;PRE&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; ' get part document&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim oPartDoc As PartDocument&lt;BR /&gt;&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; ' Set a reference to the component definition.&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim oCompDef As PartComponentDefinition&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set oCompDef = oPartDoc.ComponentDefinition&lt;BR /&gt;&lt;BR /&gt;    ' Get sketch however you need to
	Dim oSketch As Sketch
    Set oSketch = oCompDef.Sketches.Item(1)
                
    ' Create a profile.
    Dim oProfile As Profile

    Set oProfile = oSketch.Profiles.AddForSolid
    
    ' Create a pocket .25 cm deep.
    Set oExtrudeDef = oCompDef.Features.ExtrudeFeatures.CreateExtrudeDefinition(oProfile, kCutOperation)
    Call oExtrudeDef.SetDistanceExtent(0.25, kNegativeExtentDirection)
    Set oExtrude = oCompDef.Features.ExtrudeFeatures.Add(oExtrudeDef)&lt;/PRE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;</description>
      <pubDate>Tue, 30 Apr 2013 15:16:13 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899506#M131132</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-04-30T15:16:13Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899519#M131133</link>
      <description>&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;BLOCKQUOTE&gt;&lt;HR /&gt;@Anonymous wrote:&lt;BR /&gt;&lt;P&gt;&lt;SPAN&gt;&lt;SPAN&gt;Я надеюсь,&lt;/SPAN&gt; &lt;SPAN&gt;я понимаю вашу&lt;/SPAN&gt; &lt;SPAN&gt;проблему правильно&lt;/SPAN&gt;&lt;SPAN&gt;.&lt;/SPAN&gt; &lt;SPAN&gt;Вы&lt;/SPAN&gt; &lt;SPAN&gt;хотите использовать&lt;/SPAN&gt; &lt;SPAN&gt;экструзионную&lt;/SPAN&gt; &lt;SPAN&gt;эскиз&lt;/SPAN&gt;&lt;SPAN&gt;, чтобы сократить&lt;/SPAN&gt; &lt;SPAN&gt;часть?&lt;/SPAN&gt; &lt;SPAN&gt;Вы сказали, что&lt;/SPAN&gt; &lt;SPAN&gt;вся&lt;/SPAN&gt; &lt;SPAN&gt;часть создана с помощью&lt;/SPAN&gt; &lt;SPAN&gt;кода&lt;/SPAN&gt;&lt;SPAN&gt;, правильно?&lt;/SPAN&gt; &lt;SPAN&gt;Означает ли это,&lt;/SPAN&gt; &lt;SPAN&gt;у вас есть свободный&lt;/SPAN&gt; &lt;SPAN&gt;доступ к&lt;/SPAN&gt; &lt;SPAN&gt;эскизу&lt;/SPAN&gt;&lt;SPAN&gt;, который нужно вырезать&lt;/SPAN&gt; &lt;SPAN&gt;с&lt;/SPAN&gt;&lt;SPAN&gt;?&lt;/SPAN&gt; &lt;SPAN&gt;Вы должны&lt;/SPAN&gt; &lt;SPAN&gt;быть в состоянии найти&lt;/SPAN&gt;&lt;SPAN&gt;, например, в&lt;/SPAN&gt; &lt;SPAN&gt;файле помощи&lt;/SPAN&gt; &lt;SPAN&gt;API&lt;/SPAN&gt; &lt;SPAN&gt;о том, как&lt;/SPAN&gt; &lt;SPAN&gt;экструзия&lt;/SPAN&gt; &lt;SPAN&gt;эскиз.&lt;/SPAN&gt; &lt;SPAN&gt;В основном один раз&lt;/SPAN&gt; &lt;SPAN&gt;у вас есть&lt;/SPAN&gt; &lt;SPAN&gt;эскиз&lt;/SPAN&gt;&lt;SPAN&gt;, необходимо создать&lt;/SPAN&gt; &lt;SPAN&gt;профиль, вы&lt;/SPAN&gt; &lt;SPAN&gt;затем создать&lt;/SPAN&gt; &lt;SPAN&gt;определение&lt;/SPAN&gt; &lt;SPAN&gt;выдавливания&lt;/SPAN&gt;&lt;SPAN&gt;,&lt;/SPAN&gt; &lt;SPAN&gt;и, наконец,&lt;/SPAN&gt; &lt;SPAN&gt;экструзии&lt;/SPAN&gt; &lt;SPAN&gt;с использованием определения&lt;/SPAN&gt;&lt;SPAN&gt;.&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;&lt;P&gt;&lt;SPAN style="line-height: 14px;"&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="line-height: 14px;"&gt;Nice, I knew someone spoke Russian &lt;span class="lia-unicode-emoji" title=":winking_face:"&gt;😉&lt;/span&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="line-height: 14px;"&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/P&gt;&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;P&gt;Google Translate for us English speaking types:&lt;/P&gt;&lt;P&gt;I hope I understand your problem correctly. You want to use an extrusion sketch to cut part of it? You said that the entire part is created in the code, right? Does this mean you have free access to the sketch you want to cut with? You should be able to find, for example in a help file API how extrusion sketch. Basically, once you have a sketch, create a profile, you then create a definition of the extrusion, and finally, using the definition of extrusion.&lt;/P&gt;&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;</description>
      <pubDate>Tue, 30 Apr 2013 15:30:56 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899519#M131133</guid>
      <dc:creator>jdkriek</dc:creator>
      <dc:date>2013-04-30T15:30:56Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899913#M131134</link>
      <description>&lt;P&gt;как сделать вырез я знаю. так как Инвентор присваивает граням случайную позицию, мне нужно найти номер грани которую образует линия 1.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;how to make a Extrude I know. as Inventor assigns faces a random position, I need to find the number that faces forms a line 1.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;IMG alt="Безымянный.png" src="https://forums.autodesk.com/t5/image/serverpage/image-id/51690i77545B4881EF60CC/image-size/original?v=mpbl-1&amp;amp;px=-1" align="center" border="0" title="Безымянный.png" /&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Tue, 30 Apr 2013 20:03:14 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3899913#M131134</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-04-30T20:03:14Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3905657#M131135</link>
      <description>&lt;P&gt;Based on the picture I'm making this assumption, you want to find the face that a sketch line lies on.&amp;nbsp; I don't know if that's an accurate assesment of the problem or not but here's a solution to that.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;Public Sub FindFaceFromSketchLine()&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim partDoc As PartDocument&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set partDoc = ThisApplication.ActiveDocument&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; ' Have the sketch line selected.&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim line As SketchLine&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set line = ThisApplication.CommandManager.Pick( _&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; kSketchCurveLinearFilter, "Select the sketch line.")&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; ' Get the equivalent 3D line.&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim modelLine As LineSegment&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set modelLine = line.Geometry3d&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; ' Find the face that the midpoint of the line lies on.&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim filter(0) As SelectionFilterEnum&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; filter(0) = kPartFaceFilter&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim foundItems As ObjectsEnumerator&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set foundItems = partDoc.ComponentDefinition.FindUsingPoint(modelLine.MidPoint, _&lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; filter, 0.01)&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; If foundItems.Count &amp;gt; 0 Then&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; Dim foundFace As Face&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; Set foundFace = foundItems.Item(1)&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; partDoc.SelectSet.Clear&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; Call partDoc.SelectSet.Select(foundFace)&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; MsgBox "The found face is selected."&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; Else&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; MsgBox "No face was found for the selected line."&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp; End If&lt;/FONT&gt;&lt;BR /&gt;&lt;FONT face="courier new,courier" size="1"&gt;End Sub&lt;/FONT&gt;&lt;/P&gt;</description>
      <pubDate>Fri, 03 May 2013 17:37:58 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3905657#M131135</guid>
      <dc:creator>ekinsb</dc:creator>
      <dc:date>2013-05-03T17:37:58Z</dc:date>
    </item>
    <item>
      <title>Re: VBA and Inventor</title>
      <link>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3908811#M131136</link>
      <description>&lt;P&gt;Thanks for the help&lt;/P&gt;</description>
      <pubDate>Mon, 06 May 2013 04:46:09 GMT</pubDate>
      <guid>https://forums.autodesk.com/t5/inventor-programming-forum/vba-and-inventor/m-p/3908811#M131136</guid>
      <dc:creator>Anonymous</dc:creator>
      <dc:date>2013-05-06T04:46:09Z</dc:date>
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