topic Re: missing section modulus in Inventor Forum

topic Re: missing section modulus in Inventor Forum https://forums.autodesk.com/t5/inventor-forum/missing-section-modulus/m-p/5852345#M372360 Section Modulus is the second moment of area (moment of inertia) divided by the distance from the neutral axis of a beam to some fiber in the beam.  Most often one uses the distance to the extreme fiber on the outer edge of the beam because that is the highest stressed region. See: <A href="https://en.wikipedia.org/wiki/Section_modulus" target="_blank">https://en.wikipedia.org/wiki/Section_modulus</A>     If your tube is long enough, and it is not bent prior to loading, I think you can use the distance between the geometric center of the tube and the outermost edge.  In this case it would be 1.5".  See: <A href="https://en.wikipedia.org/wiki/Neutral_axis" target="_blank">https://en.wikipedia.org/wiki/Neutral_axis</A>   Model up your tube in IV, make sure to use the obvious symmetry about the part origin.  Add a cross-section sketch and use the project cut edges to get the inner and outer parameter of the tube.  Make sure that the sketch origin is at the center of the part.  Use the Edit Coordinate System command to move it if IV puts it somewhere else (RMB on the sketch in the model browser to access this command). While in that sketch, use the Region Properties tool under the Inspect tab to find the Area Moment of Inertia for that shape. Divide the Area Moment of Inertia by 1.5" to get your section modulus.   <IMG src="https://forums.autodesk.com/t5/image/serverpage/image-id/193288iF13723F52EB212B3/image-size/original?v=mpbl-1&px=-1" alt="Region Props.JPG" title="Region Props.JPG" border="0" /> Thu, 08 Oct 2015 14:22:58 GMT swalton 2015-10-08T14:22:58Z