https://forums.autodesk.com/t5/hsm-post-processor-forum/bar-puller-positioning/m-p/6084855#M27034 What exactly are you trying to do?<BR /><BR />We run our lathes with a Main program that basically calls a sub-program (which is the part cutting program) repeats a specific number of times which equals to this: (48 inch long bar - 2.0 chucking slug) / (part length + .15) = number of main cycle repeat. The .150 comes from using a .125 wide cutoff blade and allowing .0125 face stock on each end of the part or .025 face stock on the front side of the part. <BR /><BR />At the end of the parts to be ran has been reached, the main calls up a part locator move. <BR />The chuck stops, chuck opens, operator removes the last chucking slug. cycle start, chuck closes,<BR />turret does tool change to puller station, moves to new bar position, chuck opens.<BR />Operator loads new bar from the back of the machine and pushes the bar until it touches the cutoff blade.<BR />Operator clamps the chuck while holding the bar against the cutoff blade. (on some machines the spindle liners will want to pull the bar away from the cutoff blade.)<BR />Cycle start starts the program all over again for another 20 parts.<BR /><BR />We let the parts drop into the chip conveyor and separate them from the chips as both drop into a cart. Chips go into a chip bin and parts go into another cart. Basically unattended CNC turning.<BR /><BR />Only on catch with this: if you use the sub-program loop counter it will reset to zero with a control reset.<BR />To get around this a macro counter needs to be implemented. Something like this:<BR /><BR />O1000<BR />#501=20(PARTS TO BE RAN)<BR />#502=#502+1 (counter)<BR />IF#502GT#501GOTO99<BR />(MACHINING PROGRAM)<BR /><BR /><BR /><BR />N99#502=0<BR />M99<BR /><BR />Good Luck Wed, 22 Jul 2015 20:57:53 GMT Greg_Haisley 2015-07-22T20:57:53Z