topic Re: Access file tree structure. in Fusion API and Scripts Forum

Access file tree structure.

LiveLover — Tue, 08 Jun 2021 15:55:09 GMT

Hello!
Can we observe projects list and project's directory/file structure?

Thank you!

Re: Access file tree structure.

sasikanth.kollipara — Wed, 09 Jun 2021 05:54:11 GMT

Hi, Thanks for using Fusion. Are you looking for API or a place to view the structure?

You can see it in the web interface as well.

If my post answers your question, please click the "Accept Solution" button. This helps everyone find answers more quickly!

Regards,

Sas

Re: Access file tree structure.

JeromeBriot — Wed, 09 Jun 2021 07:38:40 GMT

Hello,

Here is a script that list all hubs, projects, folders and files.

Note that the code takes time to end because it gets the information from the Autodesk server.

import adsk.core, adsk.fusion, traceback import platform import os if platform.system() == 'Windows': desktopPath = os.path.join(os.getenv('USERPROFILE'), 'Desktop') else: desktopPath = os.path.join(os.path.expanduser('~'), 'Desktop') txtFile = os.path.join(desktopPath, 'DataFusion360.txt') def getFolderData(folder, level, f): for dataFile in folder.dataFiles: f.write('\n' + '\t'*level + dataFile.name + ' | ' + dataFile.id) for dataFolder in folder.dataFolders: f.write('\n' + '\t'*level + dataFolder.name + ' | ' + dataFolder.id) getFolderData(dataFolder, level+1, f) def run(context): ui = None try: app = adsk.core.Application.get() ui = app.userInterface with open(txtFile, 'w') as f: for dataHub in app.data.dataHubs: f.write(dataHub.name) for dataProject in dataHub.dataProjects: f.write('\n\t' + dataProject.name + ' | ' + dataProject.id) getFolderData(dataProject.rootFolder, 2, f) f.write('\n') ui.messageBox('End') except: if ui: ui.messageBox('Failed:\n{}'.format(traceback.format_exc()))

Re: Access file tree structure.

LiveLover — Wed, 09 Jun 2021 07:57:49 GMT

Hello @sasikanth.kollipara! Thank you for replying!
https://www.autodesk.com/products/fusion-360/collaborator
shows me

is this because I have no some (what?) subscription?

And "ViewDetails on Web" brings me to a web observer for my projects

Re: Access file tree structure.

sasikanth.kollipara — Wed, 09 Jun 2021 08:08:32 GMT

You can click Access now on the above screenshot you shared and you should be able to view the web interface.

And if you have the proper entitlement in Fusion, you are free to use this web interface for all your data management activities. You can do File operations pretty easy along with the review capabilities.

If my post answers your question, please click the "Accept Solution" button. This helps everyone find answers more quickly!

Regards,

Sas

Re: Access file tree structure.

kandennti — Wed, 09 Jun 2021 10:03:40 GMT

Hi @JeromeBriot .

I have made a similar script, but I did not do such detailed information. It's great.

It seems to be slightly faster to use the asArray method.
However, empty folders, etc. caused an error.

Also, I am using it in a Japanese environment, and due to encoding problems, I get an error when writing the file. If you are not an English-speaking user, you may experience the same error.
So, I decode the file before writing it out.

# Fusion360API Python script import adsk.core, adsk.fusion, traceback import platform import os import time if platform.system() == 'Windows': desktopPath = os.path.join(os.getenv('USERPROFILE'), 'Desktop') else: desktopPath = os.path.join(os.path.expanduser('~'), 'Desktop') txtFile = os.path.join(desktopPath, 'DataFusion360.txt') def getFolderData(folder, level, lst): try: for dataFile in folder.dataFiles.asArray(): lst.append('\t'*level + dataFile.name + ' | ' + dataFile.id) except: pass try: for dataFolder in folder.dataFolders.asArray(): lst.append('\t'*level + dataFolder.name + ' | ' + dataFolder.id) lst = getFolderData(dataFolder, level+1, lst) except: pass return lst def run(context): ui = None try: app = adsk.core.Application.get() ui = app.userInterface t = time.time() # get data lst =[] for dataHub in app.data.dataHubs.asArray(): lst.append(dataHub.name) try: for dataProject in dataHub.dataProjects.asArray(): lst.append('\t' + dataProject.name + ' | ' + dataProject.id) lst = getFolderData(dataProject.rootFolder, 2, lst) except: pass # write file with open(txtFile, 'w') as f: f.write(toDecode('\n'.join(lst))) ui.messageBox(f'Done:{time.time()-t}s') except: if ui: ui.messageBox('Failed:\n{}'.format(traceback.format_exc())) def toDecode(s): return s.encode("CP932", "ignore").decode("CP932")

It is now faster than before, but access to the data hub is still slow.

Re: Access file tree structure.

JeromeBriot — Wed, 09 Jun 2021 11:02:12 GMT

@kandennti a écrit :

Also, I am using it in a Japanese environment, and due to encoding problems, I get an error when writing the file. If you are not an English-speaking user, you may experience the same error.
So, I decode the file before writing it out.

You can also try this :

with open(txtFile, 'w', encoding='cp932') as f: