Posts: 5
Registered: ‎12-27-2006
Message 1 of 2 (181 Views)

Root Node

181 Views, 1 Replies
01-23-2007 08:53 AM
I'm trying to get the Root Node in Python but obviously I haven't quite grapsed the concept fully. Can someone give me an idea as to where I may be going wrong?

bool WireTapServerHandle::getRootNode(
WireTapNodeHandle &root
) const"

"The root node may be queried through the call getRootNode.."
"root: The root parameter is a WireTapNodeHandle object."
"Upon success, the result is placed in the root parameter."

# server = WireTapServerHandle('myMachine')
# root = WireTapNodeHandle()
# rootNode = server.getRootNode(root)
# print root
# print root.getNodeId()

Gives ""

Rather than an ID I would like to see the root node as a string, perhaps I need to call 'WireTapNodeHandle::getNodeTypeStr' once I get the concept correct?
Valued Contributor
Posts: 51
Registered: ‎11-17-2006
Message 2 of 2 (181 Views)

Re: Root Node

01-23-2007 08:22 PM in reply to: bfattorini

You're hitting a bit of silliness in the API. To see the actual ID on a WireTapNodeId object, you need to call the id() function as follows:


Yucky. A simple cast operator on our end should do the trick. We'll try to get that in to avoid the confusion.

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