Changing the elements in a list with strcat

[dmfrazier]

Using AutoLISP, I have the following list set to a variable "dwginfo" (the list was generated using the DOSLib function "dos_getfilem"):

("C:\\Drawing\\Temp\\000aaTest\\DwgConvert\\" "test1.dwg" "test1x.dwg" "test2.dwg" "test2x.dwg" "test3.dwg" "test4.dwg")

I take the first element and store it as "path":

Command: (setq path (car dwginfo))
"C:\\Drawing\\Temp\\000aaTest\\"

Then I remove the first element and store this new list as "names":

Command: (setq names (cdr dwginfo))
("test1.dwg" "test1x.dwg" "test2.dwg" "test2x.dwg" "test3.dwg" "test4.dwg")

Now, what I would like to do is create a new list consisting of each element in "names" with the path added to it (in front).

I have tried this with varying combinations of list and foreach, but the closest I can get is this:

Command: (setq dwgs (list (foreach nam names (strcat path nam))))
("C:\\Drawing\\Temp\\000aaTest\\test4.dwg")

Foreach only returns the results of the last concatenation, so that's all I get in the "list".

How can I build a list containing all of the concatenated names?

Thanks.

[hmsilva · Accepted solution]

(setq dwgs (mapcar '(lambda (x) (strcat path x))  names))

HTH
Henrique

[Kent1Cooper]

hmsilva's way is certainly more concise, but here's a way to re-arrange mostly the elements of yours to do it:

(foreach nam names (setq dwgs (cons (strcat path nam) dwgs)))

If the order needs to be the same as in the names list, you would then want to:

(setq dwgs (reverse dwgs))

[dmfrazier]

I had a feeling it would involve mapcar, but couldn't figure out how to use it.  And lambda has always been a mystery for me.

Thank you very much for that, Henrique.  It is exactly what I needed. 

[dmfrazier]

I should've thought of cons.

Thanks, Kent.  It's always nice to have alternatives (even less concise ones).

[hmsilva]

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@dmfrazier wrote:

I had a feeling it would involve mapcar, but couldn't figure out how to use it.  And lambda has always been a mystery for me.

Thank you very much for that, Henrique.  It is exactly what I needed. 

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You're welcome, dmfrazier
Glad I could help.

May be helpful this Lee Mac's explanation Mapcar & Lambda

Henrique

[Jason.Piercey]

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@dmfrazier wrote:

 And lambda has always been a mystery for me.

There are differences but essentially, for most practical purposes, Lambda  is the same as defun without the need for a name.

defun = named function

lambda = nameless function