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NODAL LOAD IN CLADDING DISTRIBUTION LOAD?

9 REPLIES 9
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Message 1 of 10
Anonymous
683 Views, 9 Replies

NODAL LOAD IN CLADDING DISTRIBUTION LOAD?

Hello,

 

How is possible that I get some nodal loads when I show the automatically generated forces of a clad??

 

Supposedly the superficial load should only be distributed as linear loads in the supporting bars.

 

Thanks in advance

9 REPLIES 9
Message 2 of 10
Anonymous
in reply to: Anonymous

Here are some pics explaningin what happening

Captura.PNG

Message 3 of 10
Artur.Kosakowski
in reply to: Anonymous

The reason is tiny inaccuracy in generation of tributary areas (see the attached picture) but if you compare value of the nodal force to the linear forces from the half of the adjoining bars you can see that it is 2e-5 of their values. What IMHO is more important is the fact that you probably wanted to define the values of loads in kG/m but having units of the model set as mm you applied them in kG/mm instead (don't the values of loads seem a little too big ? Smiley Happy )

 

If we divide the value of nodal forces by 1000*1000 they become 0s. 

 

Am I right?

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
Message 4 of 10
Anonymous
in reply to: Artur.Kosakowski

Hi, It is just a quick example file, loads are arbitrary values. Is there a way to correct this?
Message 5 of 10
Artur.Kosakowski
in reply to: Anonymous

Can't the nodal forces of 0 value be just ignored?



Artur Kosakowski
Message 6 of 10
Anonymous
in reply to: Artur.Kosakowski

Is there a way to solve this distribution regions issue?

Captura.PNG

Message 7 of 10
Artur.Kosakowski
in reply to: Anonymous

Attach the file please.



Artur Kosakowski
Message 8 of 10
Anonymous
in reply to: Artur.Kosakowski

 
Message 9 of 10
Artur.Kosakowski
in reply to: Anonymous

dir X.png

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
Message 10 of 10
Anonymous
in reply to: Artur.Kosakowski

thanks¡¡

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