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## Robot Structural Analysis

Active Contributor
Posts: 29
Registered: ‎01-26-2010

# Load distribution from purlins to beams

619 Views, 3 Replies
07-02-2012 02:23 AM

Hi there,

I cannot understand how the distribution of loads is taking place from purlins to beams.

In the attached picture I have surface loads on claddings that are distributed fine on the purlins (eg 44,45,42,43 etc). But, because I have drawn the purlins half the lenght of the building, the loads are distributed only to the beams that the purlins are stepping on. For example purlin 44 tranfers load only to 5 and 11 beams.

Is there a way to distibute loads to all beams through the purlins lenght without having to break the purling in every juction?

If I offset the purlins will I be able to use releases as the purlins are pinned at both ends?

Thanks a lot.

Product Support
Posts: 5,466
Registered: ‎04-26-2010

# Re: Load distribution from purlins to beams

07-02-2012 02:45 AM in reply to: arailos

Check the settings of your cladding ; Oneway or two? Correct Direction ?

Check display of forces generated automatically.

Rafal Gaweda
Active Contributor
Posts: 29
Registered: ‎01-26-2010

# Re: Load distribution from purlins to beams

07-02-2012 03:11 AM in reply to: Rafal.Gaweda

I had one-way x direction of load distribution, Meaning that the cladding load will be distributed on the purlins and then from the purlins to the beam as concentrated loads to the points where the purlin is stepping on the beam.

If I use two-way direction distribution the loads are distibuted trapezodially on both purlins and beams something that is not correct.

See attachments. If you look closely the distributed load at beam 11)middle one) and on the beams at the edges is uniform rectangular but on the the rest is trapezodial....

Product Support
Posts: 5,466
Registered: ‎04-26-2010

# Re: Load distribution from purlins to beams

07-02-2012 04:32 AM in reply to: arailos

See attachments. If you look closely the distributed load at beam 11)middle one) and on the beams at the edges is uniform rectangular but on the the rest is trapezodial....

Divide these beams (5 11 32 34) by nodes situated on them

Rafal Gaweda