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Forces in nodes

16 REPLIES 16
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Message 1 of 17
Anonymous
1743 Views, 16 Replies

Forces in nodes

Hi!

 

Where can I find how much force (in the x-axel) each highlited node is exposed to?

 

Best regards,

Lina

16 REPLIES 16
Message 2 of 17
Mohammed_Ata
in reply to: Anonymous

Results >> forces .

 

see the attachment . is it ok ?

Message 3 of 17
Anonymous
in reply to: Mohammed_Ata

That's what I thought, but I can't choose "Forces" for this type of structure.. what can I do about it?

Message 4 of 17
Mohammed_Ata
in reply to: Anonymous

From your attachment , it seems that you defined only walls and floors which are be described as pannels .

 

to get forces on them ... Results >> plate  and shell results

Message 5 of 17
dimogrec
in reply to: Anonymous

"Forces" results are refered to bar elements. The same goes for "Deflections" and "Stresses". As Mohammed wrote it seems you have no bar elements in your model.

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Message 6 of 17
Anonymous
in reply to: dimogrec

Does this mean that I can't get the force for one wall in my model?
Message 7 of 17
dimogrec
in reply to: Anonymous

There are different options for that

results-> diagram for buildings -> core walls (presupposed that first you need to tansform a wall to a core)

results-> core walls (table)

results -> maps  then check membrane forcesN or M, or Q

results -> Plate and shell results (table)

Also the results in "story table" have infos about walls

 

Message 8 of 17
Anonymous
in reply to: dimogrec

Hi again..

 

I've found the force in each wall after transforming them into core walls, then I've got the result in the table "Definition and results for core walls". It's here shown different results,

 

Core Wall/Story/Cut/Case

 

What I understand Cut shows two values for one wall in one story, (Cut 1 and Cut 2) on the lower edge and on the upper edge. Is this correct?

 

My question is, how can I get the result on just one Cut?

 

 

 

Not sure if this is explained enough, let me know!

 

/Lina

Message 9 of 17
Rafal.Gaweda
in reply to: Anonymous


What I understand Cut shows two values for one wall in one story, (Cut 1 and Cut 2) on the lower edge and on the upper edge. Is this correct?

 

My question is, how can I get the result on just one Cut?

 

 

 Not possible.

Copy table to Excel and delete records for Cut 1 or 2



Rafal Gaweda
Message 10 of 17
Simau
in reply to: Rafal.Gaweda

 Hi

iI continue this thread because i have a substructure to study..

Is it possible to extract the efforts in the highlighted nodes from the global model, in order to use them as simple cases.

 

Nodes.jpg

Message 11 of 17
Simau
in reply to: Simau

Just a precision,

when these nodes are in foundation, it is posible to get the efforts via the reactions, as explained here 

 

http://forums.autodesk.com/t5/robot-structural-analysis-forum/substructure-and-load-case/td-p/640251...


My question concerns the nodes of the upper levels of a building.

Message 13 of 17
Simau
in reply to: Rafal.Gaweda

Ok Rafal,

 

I remember this thread.

It was very usefull to get forces from nodes with frame structure.

With nodes in pannels, it doesn't work.

It's difficult to modify Finite Element model by introducing riigd links at the place we need information.

So, is there a mean to get directly efforts on hilighted nodes?

If exists, this method will be great.

Message 14 of 17
Simau
in reply to: Simau

Hi,

I come again about this topic.

If we need efforts on the lower nodes of  a panel, how do we proceed?

Its possible for nodes on bars, but not on nodes panels.

Message 15 of 17
Artur.Kosakowski
in reply to: Simau

results in selected panel nodes.PNG

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
Message 16 of 17
Simau
in reply to: Artur.Kosakowski

Thanks Artur

Please step by step how you get this table

Message 17 of 17
Artur.Kosakowski
in reply to: Simau

Here you are:

 

 

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski

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