FEM results

[Refaat]

Dear Sirs

Could I get advice how to get the following values for the attached example :

- The shear force value in the slab at (support node) equal to the reaction value .

- The sum. of shear forces value in the slab at( concentrated load point) equal to the concentrated load value .

- How can I get the shear stress value from shear force value at same node ? please , simple example ?

Please , take a look to the attached capture and file .

Note : If you want to use captures for explanation .Kindly , send it as attached. 

Thanks in advance .

Refaat           

[Rafal.Gaweda]

This is what you can get - attached screen shot with panel cuts, mesh size 10cm.

You should add integral values of cuts A1 and A2 or A3 and A4 or look at results of cut A5 or A6

[Refaat]

Dear  Rafal

Good morning

Thanks for your response . Please , take a look to the attached capture . I would like you to confirm if I understand the meaning of the Integral value correct or not .

Integral value = 50251.97 (KN/m)*m

Integral value per one meter = (50251.97 /2.50) =20100.788 9 (KN/m)

Applied max. shear force  to used for design = 20100.7889 (KN/m)

ACI318-08M ....Item 11.2 ....equation (11-3)

VC= 0.17 √FC bw d .....where bW= 1.00 m

then VC = (KN/m)

So , then I can compare VC with 20100.7889 (KN/m)

Kindly , Could you Confirm that ? . And what is the meaning of (Reduced value)? can I used for design or not ?

With Best Regards

Refaat

[Rafal.Gaweda]

Take a look here :

http://docs.autodesk.com/RSA/2013/ENU/filesROBOT/GUID-2C7F8C26-C452-46A3-9A0D-07C9B278233A.htm