i am do a design for a column
and a have a problen how to let robot take the young modulus of concrete and steel ? you can see in the pic ..
i have anther point
why robot in design of column taking Bdns =1.0 every time
and as you know sir it very importent factor in design equation of column results
i find it 0.50 and he took it 1.0 i need from him to calculated as what it is.
thank you
egoze
you can check the pic & file please
Solved! Go to Solution.
Solved by Artur.Kosakowski. Go to Solution.
The RC Design modules calculate values of E based on values of concrete resistance according to the formula from the selected RC design code. The parameters of steel are taken from the reinforcement bar database.
The live load you defined is the long term one with B-1 the same as the dead load
if you change your live load to the short term:
then
If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.
hiiii
thank you sir
what do you mean by ..
The RC Design modules calculate values of E based on values of concrete resistance according to the formula from the selected RC design code..
so thee is no relation between the young modulus of concrete which i definef it from
tools -job perefrance -materail ..etc
i difened it to be 24855.61 Mpa not 26521.33 Mpa
ok
now what is the furmula from where i got it ? i use E = 4700*(fc`)^0.5
how can i change 26521.33 Mpa to be 24855.61 Mpa
Can you show me how to to fixed it ,or where can find the formule in robot
thank you
egoze
For ACI 318
If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.
excactly
my problem in this eqaution 4700(fc)^0.5 ...> 4700 or ( 4743.077 ) comes when we use wc=2300kg/cm2 which means evry times i conseder the wc to be 2300kg/cm2
thank you sir 🙂
i have still small point
ise moment of inertia of steel in robot
the formula of Ise
i used 25 mm as main bar
10 mm as transfer
4 cm cover
Regards
egoze
my problem in this eqaution 4700(fc)^0.5 ...> 4700 or ( 4743.077 ) comes when we use wc=2300kg/cm2 which means evry times i conseder the wc to be 2300kg/cm2
Robot calculates Ec according to the yellow formula when wc is smaller than 160lb/ft3 and according to the red one when wc is larger than this value.
i have still small point
ise moment of inertia of steel in robot
the formula of Ise
i used 25 mm as main bar
10 mm as transfer
4 cm cover
Robot uses the exact positions of rebars. I the case as below the distance from the bottom edge to the middle rebar is 40 + 10 + 12.5 = 62.5mm whereas to the corner one is 55.6 + 12.5 = 67.1mm
If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.
hi
robot is using eq (10-14) to find EI in ACI code
how robot fid Ise
Thank you
Attachment