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CLADDING AND LOAD DISTRIBUTION

21 REPLIES 21
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Message 1 of 22
BertelliMarco1095
4588 Views, 21 Replies

CLADDING AND LOAD DISTRIBUTION

Dear all,

 

I use the cladding feature froms its addition in robot and is very usefull.

Today I was designing a rectangular slab with in the cernter a circular hole. I added a rectangular cladding and then a circle: you see on the screen that the circle forms an hole on the cladding. after the calculation if I look the the load ridistribution, i see that the hole is not considered! if I check the reaction the give the same result!

 

is this a bug or my procedure is worng? PLease find attached the example file.

Tags (1)
21 REPLIES 21
Message 2 of 22

Hello,

 

You didn't add the RSA-file to your question so I hope I did understand your question correctly.

I think you must ad the whole in your cladding as well.

 

greeting,

Henk Boelens

Message 3 of 22

It should work. If not please attach example.

 

cladwithhol.jpg



Rafal Gaweda
Message 4 of 22

now the file should be attached

Message 5 of 22

The distribution algorithm is not capable of correct detection of openings that stretch up to the edges of a cladding itself. You should either create two claddings and no opening or reduce its size.

 

If you find your post answered press the Accept as Solution button please. This will help other users to find solutions much faster. Thank you.



Artur Kosakowski
Message 6 of 22

ok

thanks very much

Message 7 of 22

Hi

 

how did you get the load distribution pattern to display like that?

Message 8 of 22
Artur.Kosakowski
in reply to: jamalsid

load distribution.PNG



Artur Kosakowski
Message 9 of 22
jamalsid
in reply to: Artur.Kosakowski

Wow, that was a fast reply!!

 

Thanks, knew it would be something simple.

Message 10 of 22
gabrielhabib89
in reply to: jamalsid

hey,

 

I am having problems with load distribution on the inclined roof, I added a load on the cladding but it is not distributed on the pannels. I put the load distibution in the right direction as seen in the attachement. It is working for the cladding on the columns.

 

Regards,

 

Gabriel Habib

Message 11 of 22

Hey,

 

This is a other photo too.

 

Regards,

 

Gabriel Habib

Message 12 of 22

Robot file please.


Rafal Gaweda
Message 13 of 22

I only aswered to another user that have problems
Message 14 of 22

hey,

 

thanks for the reply but I figured it out. the cladding were not placed correctly at the nodes.

 

Regards,

 

Gabriel Habib

Message 15 of 22

I dont know why the Cladding Load distribution is hidden. Please help me out

Message 16 of 22
balayogee10
in reply to: balayogee10

Q2 .Can some one help me to find a way to distribute the load equally on for sides?

Equally on four sides not 45 degree.

Message 17 of 22

Hi @balayogee10

 

The cladding load distribution option is based on the principle of assigning load from the tributary area which 'belongs' to given 'supporting' element. The kind of the load you described is also available in RSA. It is applicable to bar elements and doesn't require any cladding definition:

 

bar planar load.JPG 

 

If one or more of these posts answered your question, please click Accept as Solution on the posts that helped you so others in the community can find them easily.



Artur Kosakowski
Message 18 of 22

Hi @Artur.Kosakowski 

 

Is RSA not able to distribute load of a simple cladding with a uniform planar load correctly? Or is there anything I am doing wrong in this matter.

 

kmmdD66ZQ_0-1639383026766.png

 

I tried adding RSA file but it won't let do that.

 

Thanks in advance.

 

 

Message 19 of 22
Krzysztof_Wasik
in reply to: kmmdD66ZQ

Hi @kmmdD66ZQ 

Load distribution procedure assigns cladding area to defined beams.

In your case.

Krzysztof_Wasik_0-1639386101578.png

Then loads applied to assigned area are transferred to the corresponding beam.

 



Krzysztof Wasik
Message 20 of 22

Hi @Krzysztof_Wasik 

I am aware of the way of distribution, but is it possible to distribute the load correctly without needing to calculate the distribution by hand and applying it as a lineload. 
25% of the load should be placed on beam 2 in your and my case.

 

 

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