Community
Inventor Forum
Welcome to Autodesk’s Inventor Forums. Share your knowledge, ask questions, and explore popular Inventor topics.
cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

Why is this happening in ordinate dims?

2 REPLIES 2
Reply
Message 1 of 3
Anonymous
110 Views, 2 Replies

Why is this happening in ordinate dims?

I have an idw that contains (2) symmetrical ordinate dim's = 1.188". What I need it to read is 1.187" - so I dc on that dim to display the dim tolerance....in the "nominal" box it reads 1.187" with a precision of 3.123. I even checked the style of the entire ordinate set - it's correct. So why is 1.188 displaying when the tolerance says it really is 1.187? Thanks.
2 REPLIES 2
Message 2 of 3
Anonymous
in reply to: Anonymous

Is the model dimension 1.1875?  If so, it's
one of those quirks of rounding - not sure if it's possible to fix without
changing the model dim to 1.1870000.


style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
I
have an idw that contains (2) symmetrical ordinate dim's = 1.188". What I need
it to read is 1.187" - so I dc on that dim to display the dim tolerance....in
the "nominal" box it reads 1.187" with a precision of 3.123. I even checked
the style of the entire ordinate set - it's correct. So why is 1.188
displaying when the tolerance says it really is 1.187?
Thanks.
Message 3 of 3
Anonymous
in reply to: Anonymous

There are times when I have to set the significant digits to 3.1234, apply, and close the dim box. I then have to go back and change to 3.123, in order to get what I want. I know of no other way.

Hope it helps,
Jason

Can't find what you're looking for? Ask the community or share your knowledge.

Post to forums  

Autodesk Design & Make Report