You have to match the units of the parameter. For example if the units of
the param are ul and you reference a parameter in the equation that has
units of inch... (e.g....
d0 = 5 in
userparam (in units of ul) = d0*3
you will need to multiply the equation by 1 ul / 1 in
so you'd have in * 3 * 1ul / 1 in = 3 ul
It's just a matte of canceling the units. Also keep in mind IV doesn;t know
what "in" is but it know what "1 in" is. You need a value to go with the
units.
--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
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"ohunome" wrote in message
news:f163d81.-1@WebX.maYIadrTaRb...
> The units thing for User Parameters making things very difficult on me.
example: "ul/in" will not solve instead I have to fake Inventor out buy
throwing in a "1 in * ul/in" factor to get a in result. This is beyond me
can someone shed some light on how to get around this units stuff and make
inventor ignore units.