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Question about Trig functions in Paremeters

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Message 1 of 2
cwilko
1092 Views, 1 Reply

Question about Trig functions in Paremeters

Hello All

Lately it seems the only questions I have to ask is to do Parametric Trig equations.

So here we go again.

 

I am creating an equation driven part with a few Trig eqautions. (Not that difficult until now)

One equation I need to input requires the Trig function Cotangent (cot).

eg. cot (x deg / n ul) with the unit type set at (ul)

This syntax does not work.

But when I rewrite the equation as 1 ul / tan (x deg / n ul) or tan (x deg / n ul)^-1 ul I get the result that cot should give me.

 

Does Inventor not support the Cotangent, Secant or Cosecant functions?

Or am I just misrepresenting the syntax description?

Thanks Clint
Inventor 2012 Professional
1 REPLY 1
Message 2 of 2
sam_m
in reply to: cwilko

list of valid functions (in "References" -> "Use formulas and equations" -> "Functions")

 

http://wikihelp.autodesk.com/Inventor/enu/2012/Help/0073-Autodesk73/0733-Design_O733/0736-Paramete73...

 

no cot, so guess you're stuck with 1/tan



Sam M.
Inventor and Showcase monkey

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