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Member
SNOWV
Posts: 3
Registered: ‎11-06-2012
Message 1 of 5 (224 Views)

Pure tortion

224 Views, 4 Replies
11-06-2012 12:59 PM

Why in pure tortion of a round beam one diameter increases in size. In theory it shouldn't. I just put a torque on one side and fixed constrained another end.  Is this due to the way, how inventor solves it? Is there a way to minimize it?

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nannerdw
Posts: 95
Registered: ‎06-09-2008
Message 2 of 5 (216 Views)

Re: Pure tortion

11-06-2012 01:27 PM in reply to: SNOWV

This thread provides a good explanation:

https://forum.solidworks.com/thread/39134

https://forum.solidworks.com/servlet/JiveServlet/download/192901-60523/expansion.png

 

Basically, it's just an artifact of Inventor's scaling methods.  Displacement scaling is not equivalent to increasing the torque on the part.

-Using Autodesk Inventor Professional 2012
Member
SNOWV
Posts: 3
Registered: ‎11-06-2012
Message 3 of 5 (176 Views)

Re: Pure tortion

11-06-2012 09:51 PM in reply to: nannerdw

I saw that post, but it still count's as not answered. Is there a way to minimize this effect and can I believe stress results?

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karthur1
Posts: 4,212
Registered: ‎04-27-2005
Message 4 of 5 (151 Views)

Re: Pure tortion

11-07-2012 05:31 AM in reply to: SNOWV

In "theory" are you saying that the shaft diameter should not expand?  What theory are you using?

 

If you are having a problem with the way Inventor displays this, you can change the scaling to "Undeformed" if you don't want to see the deformation.

 

2012-11-07_0724.png

 

 

Kirk A.

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Member
SNOWV
Posts: 3
Registered: ‎11-06-2012
Message 5 of 5 (144 Views)

Re: Pure tortion

11-07-2012 06:31 AM in reply to: SNOWV

Well, that is the definition of pure torsion. In theory of pure tortion, each cross section along z axis is exposed to the same momentum and deplanation doesn't occure.

Well, now I think that Inventor does it in reality, not theoretically.

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