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Pure tortion

4 REPLIES 4
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Message 1 of 5
SNOWV
330 Views, 4 Replies

Pure tortion

Why in pure tortion of a round beam one diameter increases in size. In theory it shouldn't. I just put a torque on one side and fixed constrained another end.  Is this due to the way, how inventor solves it? Is there a way to minimize it?

4 REPLIES 4
Message 2 of 5
nannerdw
in reply to: SNOWV

This thread provides a good explanation:

https://forum.solidworks.com/thread/39134

https://forum.solidworks.com/servlet/JiveServlet/download/192901-60523/expansion.png

 

Basically, it's just an artifact of Inventor's scaling methods.  Displacement scaling is not equivalent to increasing the torque on the part.

Message 3 of 5
SNOWV
in reply to: nannerdw

I saw that post, but it still count's as not answered. Is there a way to minimize this effect and can I believe stress results?

Message 4 of 5
karthur1
in reply to: SNOWV

In "theory" are you saying that the shaft diameter should not expand?  What theory are you using?

 

If you are having a problem with the way Inventor displays this, you can change the scaling to "Undeformed" if you don't want to see the deformation.

 

2012-11-07_0724.png

 

 

Kirk A.

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Message 5 of 5
SNOWV
in reply to: SNOWV

Well, that is the definition of pure torsion. In theory of pure tortion, each cross section along z axis is exposed to the same momentum and deplanation doesn't occure.

Well, now I think that Inventor does it in reality, not theoretically.

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