Why in pure tortion of a round beam one diameter increases in size. In theory it shouldn't. I just put a torque on one side and fixed constrained another end. Is this due to the way, how inventor solves it? Is there a way to minimize it?
This thread provides a good explanation:
https://forum.solidworks.com/thread/39134
https://forum.solidworks.com/servlet/JiveServlet/download/192901-60523/expansion.png
Basically, it's just an artifact of Inventor's scaling methods. Displacement scaling is not equivalent to increasing the torque on the part.
I saw that post, but it still count's as not answered. Is there a way to minimize this effect and can I believe stress results?
In "theory" are you saying that the shaft diameter should not expand? What theory are you using?
If you are having a problem with the way Inventor displays this, you can change the scaling to "Undeformed" if you don't want to see the deformation.
Kirk A.
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Well, that is the definition of pure torsion. In theory of pure tortion, each cross section along z axis is exposed to the same momentum and deplanation doesn't occure.
Well, now I think that Inventor does it in reality, not theoretically.