Hello,
Could you please tell me if it is possible to load a hook that rests in a hole of a metal plate?
I have performed the calculations by hand and I would like to check them using simulation and comment on any differences if there are any.
The assembly is simple, I will add all the parts and couple of images.
Thank you in advance,
U6astik
HI!!!!
But ... what you want to study? The bar, or the hook?
Sometimes, ist's better to study each part separately or do some changes in the geometry to achieve better results.
In that case, the contact between both parts its just in two points... i believe that it will not give you real results. (convergence issues).
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Hello 🙂
I would like to study the bar. The hook is not important to me.
I'd like to study the bar on its own, however, it seems impossible to appliy a pure concentrated load at a point, which isn't an edge.
(I would assume sum of two forces acting at the half of the offset - can upload image of it to clarify it if needed)
Any thoughts on how to do that?
... it seems impossible to appliy a pure concentrated load at a point, ...
It isn't possible in the real world either, so I wouldn't even try in the virtual world (which would return a singularity Force/0 area).
You do not need the hook to test the bar.
If you want to represent the area of the bar on which the hook would exert force - Split the face to get the areas.
Because the stress will be at the Fixed end, the size of the split face where the load is applied probably doesn't matter.
Here is a test at SF about 2.
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The thing is I don't know the area and anyway, hook has a circular geometry, so it's a concentrated load (in theory).
(To my mind CAD-s like Ansys or CATIA allow concentrated loads (although I am not familiar with them), but it will take my several days to understand how to do it in either of these to CAD-s. Anyway, I would like to solve this problem in Inventor.)
U6astik wrote:(To my mind CAD-s like Ansys or CATIA allow concentrated loads.)
You can concentrate the load on whatever area you want (see the attached file in previous post).
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@Anonymous wrote:
Because the stress will be at the Fixed end, the size of the split face where the load is applied probably doesn't matter.
You´re right but I don´t think he mentioned how he will be fixing it, or did he?
Because if he were to fix the bar closer and closer to the hole, then the area will start to matter. If he fixes the opposite face as it is, he could probably do away with the hole as well.
Regards,
RM
@rmerlob wrote:
@Anonymous wrote:Because the stress will be at the Fixed end, the size of the split face where the load is applied probably doesn't matter.
You´re right but I don´t think he mentioned how he will be fixing it, or did he?
I opened the part file and found a Fixed Constraint in his file at the end opposite the hole.
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