I am a novice at Autodesk Inventor and - after a long time of searching on this forum - I decided to ask for your help. Part of my design is a plastic box of 35x35x25mm (lxwxh). I have enclosed a picture and the original AIF-file.
Two sides/faces are partly set under a 45 degree angle (done with Chamfer-function). This makes the top 20x20mm, while the bottom is 35x35mm.
In the center of the bottom I need a cylindric hole: 12mm diameter.
The hole goes inside the cube for 20mm, so the top remains covered.
So far so good, but… the hole has to be set at an angle: 90-10=80 degrees seen from the front side and 90+10=100 degrees seen from the right side.
Who can tell me how to do it?
Solved! Go to Solution.
Solved by mdavis22569. Go to Solution.
Hi CorVan,
Here is some idea for you. Please have a look at the attached file. IV2010 format.
Regards,
Igor.