Inverse linear motion

[Anonymous]

Lost my formula reference doc it would seem. Anyone have the formula handy
to make one line shorter as the other gets longer? Maybe I should add it to
the auto backup on my other system this time, eh? Thanks!
~Larry

[Anonymous]

Never mind, I remembered.
~Larry

"Larry Caldwell" wrote in message
news:379B15DE1FE69AEDD6F80903E83FF71F@in.WebX.maYIadrTaRb...
> Lost my formula reference doc it would seem. Anyone have the formula handy
> to make one line shorter as the other gets longer? Maybe I should add it
to
> the auto backup on my other system this time, eh? Thanks!
> ~Larry
>
>

[Anonymous]

Wanna share that. I thought about it when you posted, but hey, it's Sat.
night and I don't think so well on Sat. nights 🙂

"Larry Caldwell" wrote in message
news:A4FCFB5A4F8E9BA3FF2E5E2958458A3C@in.WebX.maYIadrTaRb...
> Never mind, I remembered.
> ~Larry

[Anonymous]

You have 2 parallel lines;
Make a User Parameter for one (name it "Line" maybe/whatever) and add a
value.
Make both lines that value;
We'll say we now have d0 and d1 that both equal 3.
On one side (say d1) enter:
Line/d0*3

When you make d0=2,
Then
d1=4, etc.

Least that's the way I've been doing it ... course, I'm not look'n for a
Nobel Prize in mathematics either.
~Larry

"Jimmy Carr" wrote in message
news:1C668F827AB31FD9F1ABD3C2EC4BE940@in.WebX.maYIadrTaRb...
> Wanna share that. I thought about it when you posted, but hey, it's Sat.
> night and I don't think so well on Sat. nights 🙂
>
> "Larry Caldwell" wrote in message
> news:A4FCFB5A4F8E9BA3FF2E5E2958458A3C@in.WebX.maYIadrTaRb...
> > Never mind, I remembered.
> > ~Larry
>
>

[Anonymous]

So one line increases and the other decreases by the same percentage.
Increase one line by 20% and the other decreases by 20% of its own value.
What about increasing L1 by 1 and L2 decreases by 1?

--
Laurence,

Power is nothing without Control
---


"Larry Caldwell" wrote in message
news:A95C79AFCBBD097CD395D6F7E6D808EB@in.WebX.maYIadrTaRb...
> You have 2 parallel lines;
> Make a User Parameter for one (name it "Line" maybe/whatever) and add a
> value.
> Make both lines that value;
> We'll say we now have d0 and d1 that both equal 3.
> On one side (say d1) enter:
> Line/d0*3
>
> When you make d0=2,
> Then
> d1=4, etc.
>
> Least that's the way I've been doing it ... course, I'm not look'n for a
> Nobel Prize in mathematics either.
> ~Larry
>
> "Jimmy Carr" wrote in message
> news:1C668F827AB31FD9F1ABD3C2EC4BE940@in.WebX.maYIadrTaRb...
> > Wanna share that. I thought about it when you posted, but hey, it's
Sat.
> > night and I don't think so well on Sat. nights 🙂
> >
> > "Larry Caldwell" wrote in message
> > news:A4FCFB5A4F8E9BA3FF2E5E2958458A3C@in.WebX.maYIadrTaRb...
> > > Never mind, I remembered.
> > > ~Larry
> >
> >
>
>

[Anonymous]

Oops ... typed that in wrong; that's not the proportional formula, d1 in
that formula would be 4.5 and if d0=4, d1=2.25. In this instance it just
causes the lines to inverse direction. Think you can change the "3" to get
different ratios though. Can't remember the proportional formula, maybe one
of our mathematical wizards will help us out here.
~Larry

"Laurence Yeandle" wrote
in message news:0551D780BADC38BAA473DEBF447ABDF5@in.WebX.maYIadrTaRb...
> So one line increases and the other decreases by the same percentage.
> Increase one line by 20% and the other decreases by 20% of its own value.
> What about increasing L1 by 1 and L2 decreases by 1?
>
> --
> Laurence,
>
> Power is nothing without Control
> ---
>
>
> "Larry Caldwell" wrote in message
> news:A95C79AFCBBD097CD395D6F7E6D808EB@in.WebX.maYIadrTaRb...
> > You have 2 parallel lines;
> > Make a User Parameter for one (name it "Line" maybe/whatever) and add a
> > value.
> > Make both lines that value;
> > We'll say we now have d0 and d1 that both equal 3.
> > On one side (say d1) enter:
> > Line/d0*3
> >
> > When you make d0=2,
> > Then
> > d1=4, etc.
> >
> > Least that's the way I've been doing it ... course, I'm not look'n for a
> > Nobel Prize in mathematics either.
> > ~Larry
> >
> > "Jimmy Carr" wrote in message
> > news:1C668F827AB31FD9F1ABD3C2EC4BE940@in.WebX.maYIadrTaRb...
> > > Wanna share that. I thought about it when you posted, but hey, it's
> Sat.
> > > night and I don't think so well on Sat. nights 🙂
> > >
> > > "Larry Caldwell" wrote in message
> > > news:A4FCFB5A4F8E9BA3FF2E5E2958458A3C@in.WebX.maYIadrTaRb...
> > > > Never mind, I remembered.
> > > > ~Larry
> > >
> > >
> >
> >
>
>

[Anonymous]

There is no Nobel prize in mathematics. Larry.
Just Physics, Chemistry, Medicine, Literature,Peace and the one that was
added in the latter years Economics in 1969.
Ole
"Larry Caldwell" wrote in message
news:A95C79AFCBBD097CD395D6F7E6D808EB@in.WebX.maYIadrTaRb...
> You have 2 parallel lines;
> Make a User Parameter for one (name it "Line" maybe/whatever) and add a
> value.
> Make both lines that value;
> We'll say we now have d0 and d1 that both equal 3.
> On one side (say d1) enter:
> Line/d0*3
>
> When you make d0=2,
> Then
> d1=4, etc.
>
> Least that's the way I've been doing it ... course, I'm not look'n for a
> Nobel Prize in mathematics either.
> ~Larry
>
> "Jimmy Carr" wrote in message
> news:1C668F827AB31FD9F1ABD3C2EC4BE940@in.WebX.maYIadrTaRb...
> > Wanna share that. I thought about it when you posted, but hey, it's
Sat.
> > night and I don't think so well on Sat. nights 🙂
> >
> > "Larry Caldwell" wrote in message
> > news:A4FCFB5A4F8E9BA3FF2E5E2958458A3C@in.WebX.maYIadrTaRb...
> > > Never mind, I remembered.
> > > ~Larry
> >
> >
>
>