Inventor General Discussion

Reply
*peebles, scott
Message 1 of 9 (54 Views)

incorrect parameter value??

54 Views, 8 Replies
11-04-2002 02:26 AM
I am trying to insert a parameter name (d1) into the equation field of
another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this
equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation
causing the problem? Why are parameters being multiplied be 2.54 when
inserted into the equation??

Thanks
Scott
*GCooper
Message 2 of 9 (54 Views)

Re: incorrect parameter value??

11-04-2002 03:33 AM in reply to: *peebles, scott
Are you working in both English and Metric? 2.54 is a conversion factor
number as is .03937.

I haven't seen this problem, but it sure sounds like it's trying to get an
inch value from a metric? Are both parameters using the same units?

Good luck.

gcooper


"scott peebles" wrote in message
news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> I am trying to insert a parameter name (d1) into the equation field of
> another parameter (d13).
>
> The value (d1) is showing up 2.54 times larger when inserted into this
> equation field.
>
> This parameter (d13) has a "ul" unit designation. Is this "ul"
designation
> causing the problem? Why are parameters being multiplied be 2.54 when
> inserted into the equation??
>
> Thanks
> Scott
>
>
*peebles, scott
Message 3 of 9 (54 Views)

Re:

11-04-2002 03:41 AM in reply to: *peebles, scott
It appears my inch value is being converted to centimeters, but I can't
figure why. I am working in inches. The unit designation for the problem
parameter is "ul".

"GCooper" wrote in message
news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...
> Are you working in both English and Metric? 2.54 is a conversion factor
> number as is .03937.
>
> I haven't seen this problem, but it sure sounds like it's trying to get an
> inch value from a metric? Are both parameters using the same units?
>
> Good luck.
>
> gcooper
>
>
> "scott peebles" wrote in message
> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> > I am trying to insert a parameter name (d1) into the equation field of
> > another parameter (d13).
> >
> > The value (d1) is showing up 2.54 times larger when inserted into this
> > equation field.
> >
> > This parameter (d13) has a "ul" unit designation. Is this "ul"
> designation
> > causing the problem? Why are parameters being multiplied be 2.54 when
> > inserted into the equation??
> >
> > Thanks
> > Scott
> >
> >
>
*Howard, Jeff
Message 4 of 9 (54 Views)

Re: incorrect parameter value??

11-04-2002 03:52 AM in reply to: *peebles, scott
Try entering "d1 / 1 in" or "isolate(d1;ul;in)" for the value in d13.

==================================
"scott peebles" wrote in message
news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
I am trying to insert a parameter name (d1) into the equation field of
another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this
equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation
causing the problem? Why are parameters being multiplied be 2.54 when
inserted into the equation??

Thanks
Scott
*GCooper
Message 5 of 9 (54 Views)

Re:

11-04-2002 03:52 AM in reply to: *peebles, scott
Strange. Better call your VAR and tellem it's broken and you want free beer
to compensate for your pain and suffering.

Was this part ever metric? Can you duplicate this in another part? If it's
not proprietary post it to CF and I'll take a look.

gcooper


"scott peebles" wrote in message
news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYIadrTaRb...
> It appears my inch value is being converted to centimeters, but I can't
> figure why. I am working in inches. The unit designation for the problem
> parameter is "ul".
>
> "GCooper" wrote in message
> news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...
> > Are you working in both English and Metric? 2.54 is a conversion factor
> > number as is .03937.
> >
> > I haven't seen this problem, but it sure sounds like it's trying to get
an
> > inch value from a metric? Are both parameters using the same units?
> >
> > Good luck.
> >
> > gcooper
> >
> >
> > "scott peebles" wrote in message
> > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> > > I am trying to insert a parameter name (d1) into the equation field of
> > > another parameter (d13).
> > >
> > > The value (d1) is showing up 2.54 times larger when inserted into this
> > > equation field.
> > >
> > > This parameter (d13) has a "ul" unit designation. Is this "ul"
> > designation
> > > causing the problem? Why are parameters being multiplied be 2.54 when
> > > inserted into the equation??
> > >
> > > Thanks
> > > Scott
> > >
> > >
> >
>
>
*KJohnson
Message 6 of 9 (54 Views)

Re:

11-04-2002 03:59 AM in reply to: *peebles, scott
The base unit of Inventor is centimeters hence the 2.54 coversion. You need
to make the function that has d1 in it come out as ul. If the units don't
match you get weird numbers.

KAthy Johnson
"GCooper" wrote in message
news:B567348C7EA54A6503C302F719F03F33@in.WebX.maYIadrTaRb...
> Strange. Better call your VAR and tellem it's broken and you want free
beer
> to compensate for your pain and suffering.
>
> Was this part ever metric? Can you duplicate this in another part? If it's
> not proprietary post it to CF and I'll take a look.
>
> gcooper
>
>
> "scott peebles" wrote in message
> news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYIadrTaRb...
> > It appears my inch value is being converted to centimeters, but I can't
> > figure why. I am working in inches. The unit designation for the
problem
> > parameter is "ul".
> >
> > "GCooper" wrote in message
> > news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...
> > > Are you working in both English and Metric? 2.54 is a conversion
factor
> > > number as is .03937.
> > >
> > > I haven't seen this problem, but it sure sounds like it's trying to
get
> an
> > > inch value from a metric? Are both parameters using the same units?
> > >
> > > Good luck.
> > >
> > > gcooper
> > >
> > >
> > > "scott peebles" wrote in message
> > > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> > > > I am trying to insert a parameter name (d1) into the equation field
of
> > > > another parameter (d13).
> > > >
> > > > The value (d1) is showing up 2.54 times larger when inserted into
this
> > > > equation field.
> > > >
> > > > This parameter (d13) has a "ul" unit designation. Is this "ul"
> > > designation
> > > > causing the problem? Why are parameters being multiplied be 2.54
when
> > > > inserted into the equation??
> > > >
> > > > Thanks
> > > > Scott
> > > >
> > > >
> > >
> >
> >
>
*Dotson, Sean
Message 7 of 9 (54 Views)

Re: incorrect parameter value??

11-04-2002 05:39 AM in reply to: *peebles, scott
A few ways to skin the cat but one way is to use the isolate function:

isolate(d1:ul:in) assuming that d1 is in units of inches

another is

d1/ in (again assuming that d1 is in inches)

when you use mixed units (ul and in) you get into all sorts of hairy
problems...

BTW ul stands for unitless

for more info download the tutorial "Introduction to Inventor Functions" on
my site

--
Sean Dotson, PE
http://www.sdotson.com
remove all #s from email
-----------------------------------------
"scott peebles" wrote in message
news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> I am trying to insert a parameter name (d1) into the equation field of
> another parameter (d13).
>
> The value (d1) is showing up 2.54 times larger when inserted into this
> equation field.
>
> This parameter (d13) has a "ul" unit designation. Is this "ul"
designation
> causing the problem? Why are parameters being multiplied be 2.54 when
> inserted into the equation??
>
> Thanks
> Scott
>
>
*Dotson, Sean
Message 8 of 9 (54 Views)

Re:

11-04-2002 05:40 AM in reply to: *peebles, scott
sorry Jeff, guess I should have refreshed sooner...hour and a half (wow, I'm
getting slow..)

--
Sean Dotson, PE
http://www.sdotson.com
remove all #s from email
-----------------------------------------
"Sean Dotson" wrote in message
news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYIadrTaRb...
> A few ways to skin the cat but one way is to use the isolate function:
>
> isolate(d1:ul:in) assuming that d1 is in units of inches
>
> another is
>
> d1/ in (again assuming that d1 is in inches)
>
> when you use mixed units (ul and in) you get into all sorts of hairy
> problems...
>
> BTW ul stands for unitless
>
> for more info download the tutorial "Introduction to Inventor Functions"
on
> my site
>
> --
> Sean Dotson, PE
> http://www.sdotson.com
> remove all #s from email
> -----------------------------------------
> "scott peebles" wrote in message
> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...
> > I am trying to insert a parameter name (d1) into the equation field of
> > another parameter (d13).
> >
> > The value (d1) is showing up 2.54 times larger when inserted into this
> > equation field.
> >
> > This parameter (d13) has a "ul" unit designation. Is this "ul"
> designation
> > causing the problem? Why are parameters being multiplied be 2.54 when
> > inserted into the equation??
> >
> > Thanks
> > Scott
> >
> >
>
>
*Howard, Jeff
Message 9 of 9 (54 Views)

Re:

11-04-2002 06:28 AM in reply to: *peebles, scott
8~) Absolutely no prob. Thanks for the heads up on the tutorial. I'll have
to take a look.

==================

"Sean Dotson" wrote in message
news:3A994FA074EE7D8C5E988DD24CFA177B@in.WebX.maYIadrTaRb...
sorry Jeff, guess I should have refreshed sooner...hour and a half (wow, I'm
getting slow..)

--
Sean Dotson, PE
http://www.sdotson.com
remove all #s from email
-----------------------------------------
"Sean Dotson" wrote in message
news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYIadrTaRb...
> A few ways to skin the cat but one way is to use the isolate function:
..............
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