turn on suggestions

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

Close

Inventor General Discussion

Topic Options

- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic to the Top
- Bookmark
- Subscribe
- Printer Friendly Page

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

54 Views, 8 Replies

11-04-2002 02:26 AM

I am trying to insert a parameter name (d1) into the equation field of

another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this

equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation

causing the problem? Why are parameters being multiplied be 2.54 when

inserted into the equation??

Thanks

Scott

another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this

equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation

causing the problem? Why are parameters being multiplied be 2.54 when

inserted into the equation??

Thanks

Scott

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 03:33 AM in reply to:
*peebles, scott

Are you working in both English and Metric? 2.54 is a conversion factor

number as is .03937.

I haven't seen this problem, but it sure sounds like it's trying to get an

inch value from a metric? Are both parameters using the same units?

Good luck.

gcooper

"scott peebles" wrote in message

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> I am trying to insert a parameter name (d1) into the equation field of

> another parameter (d13).

>

> The value (d1) is showing up 2.54 times larger when inserted into this

> equation field.

>

> This parameter (d13) has a "ul" unit designation. Is this "ul"

designation

> causing the problem? Why are parameters being multiplied be 2.54 when

> inserted into the equation??

>

> Thanks

> Scott

>

>

number as is .03937.

I haven't seen this problem, but it sure sounds like it's trying to get an

inch value from a metric? Are both parameters using the same units?

Good luck.

gcooper

"scott peebles"

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> I am trying to insert a parameter name (d1) into the equation field of

> another parameter (d13).

>

> The value (d1) is showing up 2.54 times larger when inserted into this

> equation field.

>

> This parameter (d13) has a "ul" unit designation. Is this "ul"

designation

> causing the problem? Why are parameters being multiplied be 2.54 when

> inserted into the equation??

>

> Thanks

> Scott

>

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 03:41 AM in reply to:
*peebles, scott

It appears my inch value is being converted to centimeters, but I can't

figure why. I am working in inches. The unit designation for the problem

parameter is "ul".

"GCooper" wrote in message

news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...

> Are you working in both English and Metric? 2.54 is a conversion factor

> number as is .03937.

>

> I haven't seen this problem, but it sure sounds like it's trying to get an

> inch value from a metric? Are both parameters using the same units?

>

> Good luck.

>

> gcooper

>

>

> "scott peebles" wrote in message

> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> > I am trying to insert a parameter name (d1) into the equation field of

> > another parameter (d13).

> >

> > The value (d1) is showing up 2.54 times larger when inserted into this

> > equation field.

> >

> > This parameter (d13) has a "ul" unit designation. Is this "ul"

> designation

> > causing the problem? Why are parameters being multiplied be 2.54 when

> > inserted into the equation??

> >

> > Thanks

> > Scott

> >

> >

>

figure why. I am working in inches. The unit designation for the problem

parameter is "ul".

"GCooper"

news:EDD4D268518F21773820C6383522F38B@in.WebX.maYI

> Are you working in both English and Metric? 2.54 is a conversion factor

> number as is .03937.

>

> I haven't seen this problem, but it sure sounds like it's trying to get an

> inch value from a metric? Are both parameters using the same units?

>

> Good luck.

>

> gcooper

>

>

> "scott peebles"

> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> > I am trying to insert a parameter name (d1) into the equation field of

> > another parameter (d13).

> >

> > The value (d1) is showing up 2.54 times larger when inserted into this

> > equation field.

> >

> > This parameter (d13) has a "ul" unit designation. Is this "ul"

> designation

> > causing the problem? Why are parameters being multiplied be 2.54 when

> > inserted into the equation??

> >

> > Thanks

> > Scott

> >

> >

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 03:52 AM in reply to:
*peebles, scott

Try entering "d1 / 1 in" or "isolate(d1;ul;in)" for the value in d13.

==================================

"scott peebles" wrote in message

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

I am trying to insert a parameter name (d1) into the equation field of

another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this

equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation

causing the problem? Why are parameters being multiplied be 2.54 when

inserted into the equation??

Thanks

Scott

==================================

"scott peebles"

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

I am trying to insert a parameter name (d1) into the equation field of

another parameter (d13).

The value (d1) is showing up 2.54 times larger when inserted into this

equation field.

This parameter (d13) has a "ul" unit designation. Is this "ul" designation

causing the problem? Why are parameters being multiplied be 2.54 when

inserted into the equation??

Thanks

Scott

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 03:52 AM in reply to:
*peebles, scott

Strange. Better call your VAR and tellem it's broken and you want free beer

to compensate for your pain and suffering.

Was this part ever metric? Can you duplicate this in another part? If it's

not proprietary post it to CF and I'll take a look.

gcooper

"scott peebles" wrote in message

news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYIadrTaRb...

> It appears my inch value is being converted to centimeters, but I can't

> figure why. I am working in inches. The unit designation for the problem

> parameter is "ul".

>

> "GCooper" wrote in message

> news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...

> > Are you working in both English and Metric? 2.54 is a conversion factor

> > number as is .03937.

> >

> > I haven't seen this problem, but it sure sounds like it's trying to get

an

> > inch value from a metric? Are both parameters using the same units?

> >

> > Good luck.

> >

> > gcooper

> >

> >

> > "scott peebles" wrote in message

> > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> > > I am trying to insert a parameter name (d1) into the equation field of

> > > another parameter (d13).

> > >

> > > The value (d1) is showing up 2.54 times larger when inserted into this

> > > equation field.

> > >

> > > This parameter (d13) has a "ul" unit designation. Is this "ul"

> > designation

> > > causing the problem? Why are parameters being multiplied be 2.54 when

> > > inserted into the equation??

> > >

> > > Thanks

> > > Scott

> > >

> > >

> >

>

>

to compensate for your pain and suffering.

Was this part ever metric? Can you duplicate this in another part? If it's

not proprietary post it to CF and I'll take a look.

gcooper

"scott peebles"

news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYI

> It appears my inch value is being converted to centimeters, but I can't

> figure why. I am working in inches. The unit designation for the problem

> parameter is "ul".

>

> "GCooper"

> news:EDD4D268518F21773820C6383522F38B@in.WebX.maYI

> > Are you working in both English and Metric? 2.54 is a conversion factor

> > number as is .03937.

> >

> > I haven't seen this problem, but it sure sounds like it's trying to get

an

> > inch value from a metric? Are both parameters using the same units?

> >

> > Good luck.

> >

> > gcooper

> >

> >

> > "scott peebles"

> > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> > > I am trying to insert a parameter name (d1) into the equation field of

> > > another parameter (d13).

> > >

> > > The value (d1) is showing up 2.54 times larger when inserted into this

> > > equation field.

> > >

> > > This parameter (d13) has a "ul" unit designation. Is this "ul"

> > designation

> > > causing the problem? Why are parameters being multiplied be 2.54 when

> > > inserted into the equation??

> > >

> > > Thanks

> > > Scott

> > >

> > >

> >

>

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 03:59 AM in reply to:
*peebles, scott

The base unit of Inventor is centimeters hence the 2.54 coversion. You need

to make the function that has d1 in it come out as ul. If the units don't

match you get weird numbers.

KAthy Johnson

"GCooper" wrote in message

news:B567348C7EA54A6503C302F719F03F33@in.WebX.maYIadrTaRb...

> Strange. Better call your VAR and tellem it's broken and you want free

beer

> to compensate for your pain and suffering.

>

> Was this part ever metric? Can you duplicate this in another part? If it's

> not proprietary post it to CF and I'll take a look.

>

> gcooper

>

>

> "scott peebles" wrote in message

> news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYIadrTaRb...

> > It appears my inch value is being converted to centimeters, but I can't

> > figure why. I am working in inches. The unit designation for the

problem

> > parameter is "ul".

> >

> > "GCooper" wrote in message

> > news:EDD4D268518F21773820C6383522F38B@in.WebX.maYIadrTaRb...

> > > Are you working in both English and Metric? 2.54 is a conversion

factor

> > > number as is .03937.

> > >

> > > I haven't seen this problem, but it sure sounds like it's trying to

get

> an

> > > inch value from a metric? Are both parameters using the same units?

> > >

> > > Good luck.

> > >

> > > gcooper

> > >

> > >

> > > "scott peebles" wrote in message

> > > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> > > > I am trying to insert a parameter name (d1) into the equation field

of

> > > > another parameter (d13).

> > > >

> > > > The value (d1) is showing up 2.54 times larger when inserted into

this

> > > > equation field.

> > > >

> > > > This parameter (d13) has a "ul" unit designation. Is this "ul"

> > > designation

> > > > causing the problem? Why are parameters being multiplied be 2.54

when

> > > > inserted into the equation??

> > > >

> > > > Thanks

> > > > Scott

> > > >

> > > >

> > >

> >

> >

>

to make the function that has d1 in it come out as ul. If the units don't

match you get weird numbers.

KAthy Johnson

"GCooper"

news:B567348C7EA54A6503C302F719F03F33@in.WebX.maYI

> Strange. Better call your VAR and tellem it's broken and you want free

beer

> to compensate for your pain and suffering.

>

> Was this part ever metric? Can you duplicate this in another part? If it's

> not proprietary post it to CF and I'll take a look.

>

> gcooper

>

>

> "scott peebles"

> news:7C2DDA8159C4FEBEC8D30503B6928708@in.WebX.maYI

> > It appears my inch value is being converted to centimeters, but I can't

> > figure why. I am working in inches. The unit designation for the

problem

> > parameter is "ul".

> >

> > "GCooper"

> > news:EDD4D268518F21773820C6383522F38B@in.WebX.maYI

> > > Are you working in both English and Metric? 2.54 is a conversion

factor

> > > number as is .03937.

> > >

> > > I haven't seen this problem, but it sure sounds like it's trying to

get

> an

> > > inch value from a metric? Are both parameters using the same units?

> > >

> > > Good luck.

> > >

> > > gcooper

> > >

> > >

> > > "scott peebles"

> > > news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> > > > I am trying to insert a parameter name (d1) into the equation field

of

> > > > another parameter (d13).

> > > >

> > > > The value (d1) is showing up 2.54 times larger when inserted into

this

> > > > equation field.

> > > >

> > > > This parameter (d13) has a "ul" unit designation. Is this "ul"

> > > designation

> > > > causing the problem? Why are parameters being multiplied be 2.54

when

> > > > inserted into the equation??

> > > >

> > > > Thanks

> > > > Scott

> > > >

> > > >

> > >

> >

> >

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 05:39 AM in reply to:
*peebles, scott

A few ways to skin the cat but one way is to use the isolate function:

isolate(d1:ul:in) assuming that d1 is in units of inches

another is

d1/ in (again assuming that d1 is in inches)

when you use mixed units (ul and in) you get into all sorts of hairy

problems...

BTW ul stands for unitless

for more info download the tutorial "Introduction to Inventor Functions" on

my site

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"scott peebles" wrote in message

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> I am trying to insert a parameter name (d1) into the equation field of

> another parameter (d13).

>

> The value (d1) is showing up 2.54 times larger when inserted into this

> equation field.

>

> This parameter (d13) has a "ul" unit designation. Is this "ul"

designation

> causing the problem? Why are parameters being multiplied be 2.54 when

> inserted into the equation??

>

> Thanks

> Scott

>

>

isolate(d1:ul:in) assuming that d1 is in units of inches

another is

d1/ in (again assuming that d1 is in inches)

when you use mixed units (ul and in) you get into all sorts of hairy

problems...

BTW ul stands for unitless

for more info download the tutorial "Introduction to Inventor Functions" on

my site

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"scott peebles"

news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> I am trying to insert a parameter name (d1) into the equation field of

> another parameter (d13).

>

> The value (d1) is showing up 2.54 times larger when inserted into this

> equation field.

>

> This parameter (d13) has a "ul" unit designation. Is this "ul"

designation

> causing the problem? Why are parameters being multiplied be 2.54 when

> inserted into the equation??

>

> Thanks

> Scott

>

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 05:40 AM in reply to:
*peebles, scott

sorry Jeff, guess I should have refreshed sooner...hour and a half (wow, I'm

getting slow..)

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"Sean Dotson" wrote in message

news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYIadrTaRb...

> A few ways to skin the cat but one way is to use the isolate function:

>

> isolate(d1:ul:in) assuming that d1 is in units of inches

>

> another is

>

> d1/ in (again assuming that d1 is in inches)

>

> when you use mixed units (ul and in) you get into all sorts of hairy

> problems...

>

> BTW ul stands for unitless

>

> for more info download the tutorial "Introduction to Inventor Functions"

on

> my site

>

> --

> Sean Dotson, PE

> http://www.sdotson.com

> remove all #s from email

> -----------------------------------------

> "scott peebles" wrote in message

> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYIadrTaRb...

> > I am trying to insert a parameter name (d1) into the equation field of

> > another parameter (d13).

> >

> > The value (d1) is showing up 2.54 times larger when inserted into this

> > equation field.

> >

> > This parameter (d13) has a "ul" unit designation. Is this "ul"

> designation

> > causing the problem? Why are parameters being multiplied be 2.54 when

> > inserted into the equation??

> >

> > Thanks

> > Scott

> >

> >

>

>

getting slow..)

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"Sean Dotson"

news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYI

> A few ways to skin the cat but one way is to use the isolate function:

>

> isolate(d1:ul:in) assuming that d1 is in units of inches

>

> another is

>

> d1/ in (again assuming that d1 is in inches)

>

> when you use mixed units (ul and in) you get into all sorts of hairy

> problems...

>

> BTW ul stands for unitless

>

> for more info download the tutorial "Introduction to Inventor Functions"

on

> my site

>

> --

> Sean Dotson, PE

> http://www.sdotson.com

> remove all #s from email

> -----------------------------------------

> "scott peebles"

> news:2DF5B03CB31D6C56EBCA2218962CBA0A@in.WebX.maYI

> > I am trying to insert a parameter name (d1) into the equation field of

> > another parameter (d13).

> >

> > The value (d1) is showing up 2.54 times larger when inserted into this

> > equation field.

> >

> > This parameter (d13) has a "ul" unit designation. Is this "ul"

> designation

> > causing the problem? Why are parameters being multiplied be 2.54 when

> > inserted into the equation??

> >

> > Thanks

> > Scott

> >

> >

>

>

- Mark as New
- Bookmark
- Subscribe
- Subscribe to RSS Feed
- Highlight
- Email to a Friend
- Report Inappropriate Content

11-04-2002 06:28 AM in reply to:
*peebles, scott

8~) Absolutely no prob. Thanks for the heads up on the tutorial. I'll have

to take a look.

==================

"Sean Dotson" wrote in message

news:3A994FA074EE7D8C5E988DD24CFA177B@in.WebX.maYIadrTaRb...

sorry Jeff, guess I should have refreshed sooner...hour and a half (wow, I'm

getting slow..)

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"Sean Dotson" wrote in message

news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYIadrTaRb...

> A few ways to skin the cat but one way is to use the isolate function:

..............

to take a look.

==================

"Sean Dotson"

news:3A994FA074EE7D8C5E988DD24CFA177B@in.WebX.maYI

sorry Jeff, guess I should have refreshed sooner...hour and a half (wow, I'm

getting slow..)

--

Sean Dotson, PE

http://www.sdotson.com

remove all #s from email

-----------------------------------------

"Sean Dotson"

news:0DBB8E096F2E6E8B5C5475107C00A198@in.WebX.maYI

> A few ways to skin the cat but one way is to use the isolate function:

..............

Search This Board

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

Announcements

The Expert Elite program is made up of customers that help other customers by sharing knowledge and exemplifying an engaging style of collaboration. To learn more, please visit our Expert Elite website.

Need installation help?

Start with some of our most frequented solutions or visit the Installation and Licensing Forum to get help installing your software.

- Privacy | Legal Notices & Trademarks | Report Noncompliance | Site map | © Copyright 2014 Autodesk Inc. All rights reserved

Except where otherwise noted, this work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Please see the Autodesk Creative Commons FAQ for more information.