I have a rough, but fully contrained, sketch I did of a pretty basic pully system where I need to find the tangent angle of the tag line as it contacts the fairlead in the system. I contrained the drawing up to this point with known dimensions, and established this last need-to-know dimension as a driven one. Using Parameters under the Manage tab, I see the "equation" for this driven, or reference, dimension, is still basically just the nominal value. Is there a way to peak under the hood and view the math that Inventor used to get this value so that I may adapt it to find the angle based on the position of the end of the tag line?
Solved! Go to Solution.
Solved by cwhetten. Go to Solution.
Isn't that basic trig?
http://en.wikipedia.org/wiki/Pythagorean_theorem
http://www.wikihow.com/Use-Right-Angled-Trigonometry
Hi and welcome to the forum!
The answer to your question is no. There is no way to see how Inventor is calculating the value of a driven dimension.
If you want an equation, you'll have to derive it yourself.
You can post your part here (or somehow give us all of the geometry) and someone might offer to derive it for you.
Cameron Whetten
Inventor 2014
Hi thank you! Thats sort of a bummer it could be handy. I'm Inventor would probably calculate them differently anyway. I've done it by hand and mapped it with a best fit polynomial, but I was hoping to be a little more exact than that.
Thank you!