I am designing a part that has the shape of a catenary. In order to make it right the first time, I want to shape the catenary af the exact equation and not by making a spline between points.
I am not a math genius nor an Inventor genius, so I someone could tell me the input (see attachment) I would be pleased!
The equation I need to draw (metric) is this: f(x) = -(2.0272/2)*(e^(x/2.0272)+e^(-x/2.0272))
The part is 3800mm wide and 2200mm high (see attachment 2)
I am looking forward to your suggestions!
Solved! Go to Solution.
I could not get this to look exactly like your picture. I think my equation is correct. Here is what I used for the equations. Set your units to Meters.
x(t) = t
yt) = -1.0136 ul * ( pow(2.71828 ul;( t / 2.0272 ul )) + pow(2.71828 ul;( -t / 2.0272 ul )))
tmin = -1.9 tMax = 1.9
Here is what this looks like. Maybe you can tweak it and get it to work. If I get some more time, I will also look at this again.
Thank you very much for your reply. I worked out perfect. I am sorry, however, to tell you that I provided you the wrong equation - no wonder that you had trouble getting it right. The correct equation is f(x)= -(1063.35/2)*(e^(x/1063.35)+e^(-x/1063.35))
Sorry for that. However, I simply change the 2.0272 with 1063.35 and there it was!
You saved my day!