Dimensioning problem

[Anonymous]

I'm having problems dimensioning from the tangent of an arc to the center of another circle. this was never an issue in Inventor 6 I was always able to dimension to quadrants or tangents of an arc or circle.

[Anonymous]

someone please help me on this its becoming a crisis mode. I have to be able to dimension to the tangent of a circle from another projected center node of a circle. I'm able to dimension from a projected line to the tangent of the circle but not from the center of another circle. any advice or tips at this point would be greatly appreciated

[Anonymous]

Hover over the centre of the one circle until you
see a green dot.  Click.  Hover over the quardrent for the tangent
until you see the green dot.  Click.

There you go.

Kathy Johnson

[Anonymous]

Okay, I'm not getting a green dot. Perhaps its a setting in Inventor. I will try to find this

[Anonymous]

Not sure that it matters, but are you dim'ing on a part sketch or an IDW?

--
Dave Jacquemotte
Automation Designer

[Anonymous]

I'm dimming on a part sketch

[Anonymous]

In a part sketch use construction geometry to go
from the one centre to the edge of the other circle and dimension the
line.

Kathy Johnson

[Anonymous]

I could be wrong but I do beleive I have discovered a bug. while in sketch mode draw two circles. from one circle center dimension to the other circles tangent. If you are capable of doing this let me know?

[Anonymous]

You can't do this as there are an infinite number of points of tangency on a
circle.
--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
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"ohunome" wrote in message
news:f163643.6@WebX.maYIadrTaRb...
> I could be wrong but I do beleive I have discovered a bug. while in sketch
mode draw two circles. from one circle center dimension to the other circles
tangent. If you are capable of doing this let me know?

[Anonymous]

I've been able to do this in Inventor 6. I don't see why you cant do it know. I've always been able to dimension to the quadrant or 3rd point on an arc in Inventor. Even autocad allows this to happen why would they take it out? Inventor dimensions always solves for the aligned, vertical or horizontal to the given sketch plane therefore there is not infinite solutions!

[Anonymous]

I don't see how you did it in R6. I just tried (to double check). Click on
the center of circle 1. Hover around the perimeter of circle 2. The
tangent glyph never appears. Because there are infinite possibilities.

Now add a line and constrain it tangent to circle 2. You can dim from the
center to this line with no problems because you've defined one specific
point of tangency.

In AutoCAD if I issue the dim command then choose the center of circle 1
then choose the tangent running osnap I am offered 2 possible points. Both
of which are points that are defined as tangency points to a line running
from the center of circle 1 to tangent points on circle 2. AutoCAD assumes
this to be what you want. And honestly it's not the way I'd want to
dimension this anyway.

Tangency and quadrants are two different things.


--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"ohunome" wrote in message
news:f163643.8@WebX.maYIadrTaRb...
> I've been able to do this in Inventor 6. I don't see why you cant do it
know. I've always been able to dimension to the quadrant or 3rd point on an
arc in Inventor. Even autocad allows this to happen why would they take it
out? Inventor dimensions always solves for the aligned, vertical or
horizontal to the given sketch plane therefore there is not infinite
solutions!

[Anonymous]

yes agree quadrants and tangencies are different things. But it would be nice to dimension horizontally or vertically in relationship to the sketch on a tangency of a circle to a point.

[Anonymous]

Sean,

You are absolutely correct.

A line entity is needed to define the (2) point(s) of tangency.

QBZ



"Sean Dotson" wrote in message
news:74619DCECA9E6D389EF7E4BA12F8BF76@in.WebX.maYIadrTaRb...

> Now add a line and constrain it tangent to circle 2. You can dim from the
> center to this line with no problems because you've defined one specific
> point of tangency.

> Tangency and quadrants are two different things.

[Anonymous]

The reason you won't see that happen is that a dimension does not have
constraints built into it. A dimension, just because it is horizontal, does
not have to remain horz if I change the geometry it's attached to. Place a
point or line (that is horz) at the point of tangency in question and then
it will lock down the sketch.

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"ohunome" wrote in message
news:f163643.10@WebX.maYIadrTaRb...
> yes agree quadrants and tangencies are different things. But it would be
nice to dimension horizontally or vertically in relationship to the sketch
on a tangency of a circle to a point.

[Anonymous]

You're just loving this new images rule aren't you...

--
Sean Dotson, PE
http://www.sdotson.com
Check the Inventor FAQ for most common questions
www.sdotson.com/faq.html
-----------------------------------------------------------------------
"Quinn Zander" wrote in message
news:C47D4CA01D9B6CD69954EDE837D1B4C8@in.WebX.maYIadrTaRb...
> Sean,
>
> You are absolutely correct.
>
> A line entity is needed to define the (2) point(s) of tangency.
>
> QBZ
>
>
>
> "Sean Dotson" wrote in message
> news:74619DCECA9E6D389EF7E4BA12F8BF76@in.WebX.maYIadrTaRb...
>
> > Now add a line and constrain it tangent to circle 2. You can dim from
the
> > center to this line with no problems because you've defined one specific
> > point of tangency.
>
> > Tangency and quadrants are two different things.
>
>


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[Anonymous]

Am I missing something? make a line from the center of the circle, trim at the circumference. Make a line from the center of the other circle to the endpoint on the first line. Apply a perp constraint to the two lines.
That should do it.

Be aware that if ANYTHING on the two circles is unconstrained, you get strange results.

Tom