hello to all,
I'm a new french member. I have many problems with parametric equation.
In deed, I would like to make a formula for a dimension with Cube root or Power (1/3).
Is it possible with Inventor ?
Thanks in advance for your helps.
Solved! Go to Solution.
Solved by nightsheart. Go to Solution.
Solved by SBix26. Go to Solution.
Solved by -niels-. Go to Solution.
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
Thanks for your answer.
Nevertheless, I have already saw this page.
I can make this formula :
(12 nd) ^ ( 1 nd / 3 nd ) * 1 mm
But, if I put a variable (quote) for example :
d0 ^ ( 1 nd / 3 nd ) * 1 mm
It's doesn't work.
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
The parameter d0 already keep inside the unit mm. Try
d0 ^ 1/3
or the same (d0)^ 1 u l/ 3ul
I hope that it helps you.
Welcome in this forum
Admaiora
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oops ^2 Niels...
Admaiora
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This is how i set it up, though i'm not entirely sure about the resulting value.
It gives a warning, but all that says is that the unit type (2nd column) isn't what the formula gives out. (mm^0,333)
Not sure if this is helpfull...
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
d0 ^ 1/3
neither?
Admaiora
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Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
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Non of the solution work... For Niels : I have the same result but 12^(1/3) = 2.89... and not 10.62...
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
Yes, i went on memory, but now that i am tryng Niels is right.
It looks like quite aproblem with units in parameters..
Admaiora
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It's work but the dimension becomes 120 instead of 12.
See picture below :
Hmm... interesting, so if you have the starting value as unitless instead of mm you can get the correct value.
Even though the help page states that "expr1" can be "any" type...
@nightsheart For this to work, you have to turn your dimension into a unitless value.
I find this to be rather unintuitive, but here's another image:
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands
The problem is the units: the cube root of a millimeter dimension is in mm^(1/3), which is nonsense. Try this: ( d0 / 1 mm ) ^ ( 1 ul / 3 ul ) * 1 mm
Sam B
Inventor 2012 Certified Professional
Inventor Professional 2015 Update 1
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Just to add one last thing:
This also works, it also made me laugh as it just adds to the unit confusion when looking at it.
i just typed it like "pow(d2/1;1/3)*1mm" and inventor added the unit types as shown.
Still, this might be a little better than having to make an extra parameter just to convert the dimension to unitless.
Niels van der Veer
Inventor professional user & 3DS Max enthusiast
Vault professional user/manager
The Netherlands