Drafting Techniques

Drafting Techniques

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*Z, J B
Message 1 of 16 (778 Views)

ENTERING SURVEYOR COORDINATES TO INPUT PROPERTY BOUNDARIES

778 Views, 15 Replies
07-02-2003 06:42 AM
HELLO,
IN EITHER ACAD 2002 OR ADT 3.3 (OR 2004) IS THERE A WAY TO ENTER SURVEYOR
COORDINATE INFO TO DRAW LINES OF A PROPERTY: SUCH AS 'NORTHING COORDINATES'
LIKE...(479.30' @ N 80° 10'09"E) ETC...??

THANKS FOR ANY HELP,
-J
*ffejgreb
Message 2 of 16 (778 Views)

Re: ENTERING SURVEYOR COORDINATES TO INPUT PROPERTY BOUNDARIES

07-02-2003 06:42 AM in reply to: *Z, J B
"Units" - angle type of "Surveyors Units"
*jonesr
Message 3 of 16 (778 Views)

Re:

07-02-2003 11:22 AM in reply to: *Z, J B
With UNITS set to decimal linear and Surveyor angular:
LINE
pick start point, then
@479.30
"ffejgreb" wrote in message
news:f1741be.0@WebX.maYIadrTaRb...
> "Units" - angle type of "Surveyors Units"
>
>
*McSwain, R.K.
Message 4 of 16 (778 Views)

Re:

07-02-2003 09:38 PM in reply to: *Z, J B
Note: The units DO NOT have to be set any certain way to enter polar coordinates.

"jonesr" wrote in message news:5D19C35893541BE35CE42D0926583397@in.WebX.maYIadrTaRb...
> With UNITS set to decimal linear and Surveyor angular:
> LINE
> pick start point, then
> @479.30 >
> "ffejgreb" wrote in message
> news:f1741be.0@WebX.maYIadrTaRb...
> > "Units" - angle type of "Surveyors Units"
> >
> >
>
>
*Jessup, Allen
Message 5 of 16 (778 Views)

Re:

07-03-2003 04:40 AM in reply to: *Z, J B
You mean that if the units are set to architectural that you will still get
a 439.30 foot line with the example below?

Allen

"R.K. McSwain" wrote in message
news:smileyvery-happy:686132501D6A1117193DE7D605E94D5@in.WebX.maYIadrTaRb...
> Note: The units DO NOT have to be set any certain way to enter polar
coordinates.
>
> "jonesr" wrote in message
news:5D19C35893541BE35CE42D0926583397@in.WebX.maYIadrTaRb...
> > With UNITS set to decimal linear and Surveyor angular:
> > LINE
> > pick start point, then
> > @479.30 > >
*McSwain, R.K.
Message 6 of 16 (778 Views)

Re:

07-03-2003 05:51 AM in reply to: *Z, J B
You will get a 439.30 "unit" long line. AutoCAD doesn't know or care about what that "unit" is. True, if you are in Arch units and then turn around and list this line, it will report 36'-7", but that's just AutoCAD *reporting* the line in Feet/Inches because you set the units to Arch. The line is still 439 "units" long, those units just happen to be inches.

My main point was that you do not have to set your angle type to "surveyor's units" in order to enter polar coordinates.

"Allen Jessup" wrote in message news:21EEABCFACD8B4D3AD2AB494F7B419F5@in.WebX.maYIadrTaRb...
> You mean that if the units are set to architectural that you will still get
> a 439.30 foot line with the example below?
>
> Allen
>
> "R.K. McSwain" wrote in message
> news:smileyvery-happy:686132501D6A1117193DE7D605E94D5@in.WebX.maYIadrTaRb...
> > Note: The units DO NOT have to be set any certain way to enter polar
> coordinates.
> >
> > "jonesr" wrote in message
> news:5D19C35893541BE35CE42D0926583397@in.WebX.maYIadrTaRb...
> > > With UNITS set to decimal linear and Surveyor angular:
> > > LINE
> > > pick start point, then
> > > @479.30 > > >
>
>
*jonesr
Message 7 of 16 (778 Views)

Re:

07-03-2003 10:37 AM in reply to: *Z, J B
Cool R.K. - I never knew you could input surveyors angles with units set
otherwise. Thanks.

"R.K. McSwain" wrote in message
news:C79BCD8ABDCF290EFBC1D44A3E6FDD8F@in.WebX.maYIadrTaRb...
> You will get a 439.30 "unit" long line. AutoCAD doesn't know or care about
what that "unit" is. True, if you are in Arch units and then turn around and
list this line, it will report 36'-7", but that's just AutoCAD *reporting*
the line in Feet/Inches because you set the units to Arch. The line is still
439 "units" long, those units just happen to be inches.
>
> My main point was that you do not have to set your angle type to
"surveyor's units" in order to enter polar coordinates.
>
> "Allen Jessup" wrote in message
news:21EEABCFACD8B4D3AD2AB494F7B419F5@in.WebX.maYIadrTaRb...
> > You mean that if the units are set to architectural that you will still
get
> > a 439.30 foot line with the example below?
> >
> > Allen
> >
> > "R.K. McSwain" wrote in message
> > news:smileyvery-happy:686132501D6A1117193DE7D605E94D5@in.WebX.maYIadrTaRb...
> > > Note: The units DO NOT have to be set any certain way to enter polar
> > coordinates.
> > >
> > > "jonesr" wrote in message
> > news:5D19C35893541BE35CE42D0926583397@in.WebX.maYIadrTaRb...
> > > > With UNITS set to decimal linear and Surveyor angular:
> > > > LINE
> > > > pick start point, then
> > > > @479.30 > > > >
> >
> >
*Jessup, Allen
Message 8 of 16 (778 Views)

Re:

07-07-2003 05:50 AM in reply to: *Z, J B
Your right about getting 439.30 units. But if you are in a drawing where 1
drawing units is equal to one inch and try to input a distance in feet in
that manner you will get a line that is 1/12 of what it should be in
comparison to the rest of the drawing.
Your also right about not having to be set to Surveyors Units to enter
Bearings. I would have never have thought to try that.

Allen

"R.K. McSwain" wrote in message
news:C79BCD8ABDCF290EFBC1D44A3E6FDD8F@in.WebX.maYIadrTaRb...
> You will get a 439.30 "unit" long line. AutoCAD doesn't know or care about
what that "unit" is. True, if you are in Arch units and then turn around and
list this line, it will report 36'-7", but that's just AutoCAD *reporting*
the line in Feet/Inches because you set the units to Arch. The line is still
439 "units" long, those units just happen to be inches.
>
> My main point was that you do not have to set your angle type to
"surveyor's units" in order to enter polar coordinates.
>
*McSwain, R.K.
Message 9 of 16 (778 Views)

Re:

07-07-2003 06:11 AM in reply to: *Z, J B
"Allen Jessup" wrote
> Your right about getting 439.30 units. But if you are in a drawing where 1
> drawing units is equal to one inch and try to input a distance in feet in
> that manner you will get a line that is 1/12 of what it should be in
> comparison to the rest of the drawing.

You are right, but if I were in a drawing where each unit was an inch and I wanted a 439.9 foot line, I would input a distance of 439.9*12.

[Or you could use (cvunit 439.9 "ft" "in") to specify the distance.]
*Turvill, Paul
Message 10 of 16 (778 Views)

Re:

07-07-2003 09:54 AM in reply to: *Z, J B
... or just 439.9' -- the foot symbol automatically does the *12 if you're
using architectural (inch) units.
___

"R.K. McSwain" wrote in message
news:489E5891F6670B6EE637F44459731672@in.WebX.maYIadrTaRb...
>
> You are right, but if I were in a drawing where each unit was an inch and
I wanted a 439.9 foot line,
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