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- Curve off One Tangent..?

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173 Views, 4 Replies

02-09-2005 03:36 PM

Hello.. Drawing up a property boundary that happens to consist of many curves. In my old Cad, R14, I could draw the Radial to the curve, and then do a "Curve off One Tangent" and draw the curve by punching in the Delta/Length, and Radius.. In Civil 3d, I cant seem to find anyway where to draw Curves off Tangents, or between 2 tangents, or anything remotely close to what used to be on R14. In fact, it took me three days just to figure out how to do Lines By Direction. And, that was by typing "Line", the typing 'BD. PLease, someone, tell me there is an easier way...

Thanks,

=-Ben

Thanks,

=-Ben

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02-09-2005 04:26 PM in reply to:
soundengine

Can one assume that you have the "Transparent Commands" toolbar visible?
There are a few tools there & using them with regular AutoCad commands, most
any configuration can be accomplished. The easiest one is to use the fillet
(radius) command.
Bill
"soundengine" wrote in message
news:12414895.1107992237398.JavaMail.jive@jiveforum2.autodesk.com...
> Hello.. Drawing up a property boundary that happens to consist of many
curves. In my old Cad, R14, I could draw the Radial to the curve, and then
do a "Curve off One Tangent" and draw the curve by punching in the
Delta/Length, and Radius.. In Civil 3d, I cant seem to find anyway where to
draw Curves off Tangents, or between 2 tangents, or anything remotely close
to what used to be on R14. In fact, it took me three days just to figure
out how to do Lines By Direction. And, that was by typing "Line", the
typing 'BD. PLease, someone, tell me there is an easier way...
>
> Thanks,
> =-Ben

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02-09-2005 05:00 PM in reply to:
soundengine

Ahh.. Not bad.. It is a start.

So, I am drawing a line that we will say is N 35D20'22" E, 200ft.

At the end is an arc,

D = 110d36'35"

R = 110'

L = 212.36,

which then connects to a reverse arc of:

D = 28d27'10"

R = 110'

L = 54.63'

Which, then connects into a line going elsewhere.

Can someone here please explain to me how they would calc this on Civil 3d? Back in R14 I would go:

1)Line By Direction... First Line.

2)Curve off Tangent.... First Arc done.

3)Curves-> Compound or Reverse Curves.... Second Arc Done.

4)Line By Direction.... Continue with the rest of the project.

Keep in mind that I only have Delta's, Radius, and Length.. So I cant do the angles by decimal.. Lets assume that all lines are tangent with the arcs.

I hate to be a pest about this, but this IS my job... hehe, and I have no idea how to use C3d... a Book would have been nice...

But, this forum has been very useful for me.

Thanks,

=-Ben

So, I am drawing a line that we will say is N 35D20'22" E, 200ft.

At the end is an arc,

D = 110d36'35"

R = 110'

L = 212.36,

which then connects to a reverse arc of:

D = 28d27'10"

R = 110'

L = 54.63'

Which, then connects into a line going elsewhere.

Can someone here please explain to me how they would calc this on Civil 3d? Back in R14 I would go:

1)Line By Direction... First Line.

2)Curve off Tangent.... First Arc done.

3)Curves-> Compound or Reverse Curves.... Second Arc Done.

4)Line By Direction.... Continue with the rest of the project.

Keep in mind that I only have Delta's, Radius, and Length.. So I cant do the angles by decimal.. Lets assume that all lines are tangent with the arcs.

I hate to be a pest about this, but this IS my job... hehe, and I have no idea how to use C3d... a Book would have been nice...

But, this forum has been very useful for me.

Thanks,

=-Ben

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02-09-2005 06:28 PM in reply to:
soundengine

Well, this is just geometry. Offset your 200 tangent 110', the end of the
line will be the radius point of the curve start a curve (arc) with the 110'
radius. Use the "lengthen" command for L=211.36. (or use the "D"x2 angle
to locate the end of the curve.)
"soundengine" wrote in message
news:9042186.1107997258929.JavaMail.jive@jiveforum2.autodesk.com...
> Ahh.. Not bad.. It is a start.
>
> So, I am drawing a line that we will say is N 35D20'22" E, 200ft.
>
> At the end is an arc,
> D = 110d36'35"
> R = 110'
> L = 212.36,
>
> which then connects to a reverse arc of:
> D = 28d27'10"
> R = 110'
> L = 54.63'
>
> Which, then connects into a line going elsewhere.
>
> Can someone here please explain to me how they would calc this on Civil
3d? Back in R14 I would go:
> 1)Line By Direction... First Line.
> 2)Curve off Tangent.... First Arc done.
> 3)Curves-> Compound or Reverse Curves.... Second Arc Done.
> 4)Line By Direction.... Continue with the rest of the project.
>
> Keep in mind that I only have Delta's, Radius, and Length.. So I cant do
the angles by decimal.. Lets assume that all lines are tangent with the
arcs.
> I hate to be a pest about this, but this IS my job... hehe, and I have no
idea how to use C3d... a Book would have been nice...
>
> But, this forum has been very useful for me.
> Thanks,
> =-Ben

- Mark as New
- Bookmark
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02-10-2005 02:28 PM in reply to:
soundengine

Sounds like we're going to be traversing through a lot of radius pts and
adding arcs until the survey module is released.
"soundengine" wrote in message
news:12414895.1107992237398.JavaMail.jive@jiveforum2.autodesk.com...
> Hello.. Drawing up a property boundary that happens to consist of many
curves. In my old Cad, R14, I could draw the Radial to the curve, and then
do a "Curve off One Tangent" and draw the curve by punching in the
Delta/Length, and Radius.. In Civil 3d, I cant seem to find anyway where to
draw Curves off Tangents, or between 2 tangents, or anything remotely close
to what used to be on R14. In fact, it took me three days just to figure
out how to do Lines By Direction. And, that was by typing "Line", the
typing 'BD. PLease, someone, tell me there is an easier way...
>
> Thanks,
> =-Ben

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